A curved bar ABC is subjected to two equal loads in opposite direction as shown in figure The axis of bar forms a semicircle of radius R. Draw shear force and bending moment diagram for given bar ABC . . B P A R R

For the truss in figure below, the cross-sectional area of the truss members is A=500 mm² and Young's modulus E= 200 GPa. Let P = 93.7 kN. 1 m √3 m B Ø D 1 m √3 m F Determine: a) Strain energy for truss AC. Enter your answer in Jto 2 decimal places. b) Strain energy for truss AB. Enter your answer in J to 2 decimal places. c) Strain energy for truss BC. Enter your answer in J to 2 decimal places. d) Strain energy for truss BD. Enter your answer in J to 2 decimal places. e) Strain energy for truss DC. Enter your answer in J to 2 decimal places. f) Strain energy for truss DF. Enter your answer in J to 2 decimal places. g) Strain energy for truss FC. Enter your answer in J to 2 decimal places. h) Strain energy for truss CE. Enter your answer in Jto 2 decimal places. i) The displacement at point A. Enter your answer in mm to 2 decimal places. A

9 Consider the plane truss with load Pas shown in the figure. Let the horizontal and vertical reactions at the joint B be Hg and V, respectively and Vc be vertical reaction at the joint C. 2 exhoM S SLO 60° - II B A 60° D L 60° F 60° KLA G P с Which one of the following sets gives the correct values of VB, HB and V? (a) VB = 0; HB = 0; Vc = P (b) VB P/2; HB = 0; Vc = P/2 (c) VB = P/2; HB = P (sin60°); Vc = P/2 (d) VB = P; HB = P (cos(60°); Vc = 0 [2016

The three-bar truss ABC shown in the figure has a span L = 3 m and is constructed of steel pipes having cross-sectional area A = 3,900 mm2 and modulus of elasticity E = 200 GPa. A load P = 650,099 Newton acts horizontally to the right at joint C.        Note that point A is fixed, and point B is immovable in vertical direction but movable in horizontal direction.                              Find: (a) the axial forces in the bars, based on the force equilibrium of points C and B, (b) the strain energy of the truss (i.e., the total strain energy of bars AC, BC and AB), (c) the horizontal displacement of point C, based on the Work-energy principle.  Hint: 1. The lengths of AC and BC are: LAC = LBC = L sin 45° = 2,121 mm 2. For an axial member, the strain energy is × EA × 2 Force Length