A cosmic-ray proton in interstellar space has an energy of 10.0 MeV and executes a circular orbit having a radius equal to that of Mercury’s orbit around the Sun (5.80 × 1010m). What is the magnetic field in that region of space?

A cosmic ray electron moves at 7.60 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.00 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?

Problem 22:   A proton moves in a circular path of the same radius as a cosmic ray electron moving at 9.5 × 106 m/s perpendicular to the Earth’s magnetic field at an altitude where the field strength is 1.0 × 10-5 T. Part (a)  What will the speed of the proton be in m/s? vp = ______ Part (b)  What would the radius of the path be in meters if the proton had the same speed as the electron?  rp,v = ______ Part (c)  What would the radius be in meters if the proton had the same kinetic energy as the electron? rp,E = ______ Part (d)  What would the radius be in meters if the proton had the same momentum as the electron? rp,p = ______

(a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.25 x 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.05 × 10-5 T? m/s (b) What would the radius (in m) of the path be if the proton had the same speed as the electron? (c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? (d) What would the radius (in m) be if the proton had the same momentum as the electron?