a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.45 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.25 ✕ 10−5 T? b) What would the radius (in m) of the path be if the proton had the same speed as the electron? c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? d) What would the radius (in m) be if the proton had the same momentum as the electron?

Let the field be the Earth's magnetic field, at 4 * 10 ^ - 5 T. The electron follows a circular path of radius 4 m. Find the speed of the electron, given that e / m for the electron is 1.759 * 10 ^11 * Ck * g ^ - 1

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.215 T. If the kinetic energy of the electron is 4.20 × 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μm

A singly charged positive ion has a mass of 2.46 x 10-26 kg. After being accelerated through a potential difference of 242 V, the ion enters a magnetic field of 0.590 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field. cm

1. An electron has a velocity v = (2 x 106 m/s) i +(3.0x 106 m/s)j moves through a uniform magnetic field B = (0.030 T) ? - (0.15 T)j. (a) Find the force on the electron due to the magnetic field. (b) mass of electron is 9.11 x 10-31 kg what will be the radius of the circular path for the electron in the magnetic field?

An electron moves in a circular path with a speed of 1.41 x 10' m/s in the presence of a uniform magnetic field with a magnitude of 1.92 mT. The electron's path is perpendicular to the field. (a) What is the radius (in cm) of the circular path? cm (b) How long (in s) does it take the electron to complete one revolution?

A singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T.   (Note that the charge of an electron is e = 1.6 x 10−19 C.)   a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.240 T. If the kinetic energy of the electron is 4.10 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μm

-27 kg is The charge of an electron and a proton are both equal to q = 1.602 x 10-19 but the mass of a proton mp = 1.673 x 10 much larger than the mass of an electron me = 9.11 x 10-31 kg. If a proton and an electron move at the same speed in a circular path in a uniform magnetic field, what is the ratio of the radius of the proton's circular path r, to the radius of the electron's circular path Image size: s ML Max re. In other words what is rp/re? Note: the picture of the circular paths for the electron and proton are not drawn to scale. メ re Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8