A coil has 180 turns enclosing an area of 10.4 cm2cm2 . In a physics laboratory experiment, the coil is rotated during the time interval 0.046 ss  from a position in which the plane of each turn is perpendicular to Earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 5.00×10−5 TT .

A magnetic field has a magnitude of 0.0017 T, and an electric field has a magnitude of 5.7 × 10³ N/C. Both fields point in the same direction. A positive 2.1-µC charge moves at a speed of 4.6 × 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number i Units HHI 90° B E

A point charge moving in a magnetic field of 1.24 Tesla experiences a force of 0.714·10-11 N. The velocity of the charge is perpendicular to the magnetic field. In this problem, we use the points of the compass and `into' and `out of' to indicate directions with respect to the page. If the magnetic field points west and the force points out of the page, then select True or False for the charge Q.   True False Q is positive, moving south. True False Q is negative, moving east. True False Q is negative, moving north. True False Q is negative, moving south. True False Q is positive, moving north

A particle with charge 1.53 x 10^-6 C moves at 2.44 x 10^6 m/s through a magnetic field of strength 2.13 T. The angle between the particle s velocity and the magnetic field direction is 31.3 degrees and the particle undergoes an acceleration of 11.3 m/s^2. What is the particle s mass? 9.0 kg 15.8 kg 0.37 kg 4.5 kg

A proton moving at 5.50 x 106 m/s through a magnetic field of magnitude 1.77 T experiences a magnetic force of magnitude 7.30 × 10-13 N. What is the angle between the proton's velocity and the field? Step 1 The magnitude of the force on a moving charge in a magnetic field is FB = qvB sin 8, and, solving for the angle, we have the following. 8 sin -1 = sin-¹ B qvB 1.60 x 10-19 c)([ x 10-13 N |× 106 m/s) (

A proton moves with a speed of 207258 m/s. It is traveling in the x y plane. A magnetic field of 2.1 mT is pointing in the z-direction. What is the radius (in meters) of the circular path this proton will follow?

A particle with mass 3×10−2 kgkg and charge +7 μCμC enters a region of space where there is a magnetic field of 1 TT that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 17 m/s2m/s2 . What is the speed of the particle when it enters the magnetic-field region? Express your answer in meters per second.

A proton moves at a speed of 2.4 × 107 m/s at right angles to a magnetic field with a magnitude of 0.25 T. Find the magnitude of the acceleration of the proton. The elemental charge is 1.60 × 10−19 C. Answer in units of m/s

A charge of -8.84 μC is traveling at a speed of 6.02 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 55.1o. A force of magnitude6.02 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?

A loop of wire with radius r= 0.081 m is in a magnetic field with magnitude B as shown in the graph. B changes from B1 = 0.34 T to B2= 6.5 T in At = 7.5 s at a constant rate. Express the magnetic flux going through a loop of radius r assuming a constant magnetic field B. Express the change in the magnetic flux going through this loop, AP, in terms of B , B2 and r. Calculate the numerical value of 4P in T m². Express the magnitude of the average induced electric field, E, induced in the loop in terms of 4P, r and At. E = Calculate the numerical value of E in N/C. E =