College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A small charged particle (mass = 240 µkg ; charge = - 480 µcoul) travels through a region of space where the gravitational field is negligible and there are no magnetic fields. At a point, the particle encounters an electric field Ë = (2500)î + (- 6250)ĵ N/coul ; assuming that the only force acting on the particle is that due to the electric field, what is the direction (angle measured with respect to the + x axis) of the particle's acceleration?arrow_forwardAn electron has a mass of 9.11×10^-31 kg and a charge of -1.60×10^-19 C it moves in a magnetic field of strength 5.00×10^-4 T in a circle at a velocity of 2.00×10^6 m/s what is the radius of the circle.arrow_forwardA proton moves in a circular path of the same radius as a cosmic ray electron moving at 6.5 × 106 m/s perpendicular to the Earth’s magnetic field at an altitude where the field strength is 1.0 × 10-5 T . A) What will the speed of the proton be in m/s? B) What would the radius of the path be in meters if the proton had the same speed as the electron? C) What would the radius be in meters if the proton had the same kinetic energy as the electron? D) What would the radius be in meters if the proton had the same momentum as the electron?arrow_forward
- A magnetic field has a magnitude of 0.00090 T, and an electric field has a magnitude of 4.1 x 103 N/C. Both fields point in the same direction. A positive 2.1-µC charge moves at a speed of 2.5 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number MI Units B HI 90°arrow_forwardA magnetic field has a magnitude of 0.0018 T, and an electric field has a magnitude of 3.9 × 10³ N/C. Both fields point in the same direction. A positive 2.3-µC charge moves at a speed of 3.3 × 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number i Units B V + 9 90° 1>arrow_forwardQuestion is attached, Thanks a lotarrow_forward
- An electron in a magnetic field moves along a circle with a radius of 7.0 m and a speed that follows:vt(t) = v0t/t0where t0 = 0.9 s and v0 = 209 m/s.Find the magnitude of the (total) acceleration at t = 0.2 seconds.(in m/s^2) a. 163.87 b. 191.73 c. 224.33 d. 262.46 e. 307.08arrow_forwardThe figure below shows two wires carrying currents of I = 5.15 A in opposite directions, separated by a distance d. Assume d = 9.3 cm. P₂ -2d- Ⓡ (a) Find the magnitude (in µT) and direction of the net magnetic field at a point halfway between the wires. magnitude 44.3 ✔HT direction magnitude direction into the page 1P (b) Find the magnitude (in µT) and direction of the net magnetic field at point P₁, 9.3 cm to the right of the wire on the right. 1' ✔HT 5.54 out of the page ---Select--- く (c) Find the magnitude (in μT) and direction of the net magnetic field at point P₂, 2d = 18.6 cm to the left of the wire on the left. 1.84 UT magnitude direction out of the page ---Select-- ✓✓ (d) What If? Repeat parts (a) through (c) for the case where both wires carry currents in the same direction, upward in the figure. Find the magnitude (in µT) and direction of the net magnetic field at a point halfway between the wires. magnitude HT direction -Select- くく 1' Find the magnitude (in UT) and…arrow_forwardA cosmic ray electron moves at 7.90 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.10 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?arrow_forward
- A particle with charge 4.16 x 10^-6 C moves at 5.78 x 10^6 m/s through a magnetic field of strength 2.58 T. The angle between the particle s velocity and the magnetic field direction is 35.1 degrees and the particle undergoes an acceleration of 11.9 m/s^2. What is the particle s mass? 17.9 kg 3.00 kg 6.0 kg 7.1 kgarrow_forwardA charge of -8.85 µC is traveling at a speed of 8.38 × 106 m/s in a region of space where there is a magnetic field. The angle between the -3 velocity of the charge and the field is 51.9º. A force of magnitude8.62 × 10-³ N acts on the charge. What is the magnitude of the magnetic field?arrow_forwardA cosmic ray electron moves at 7.60 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.00 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?arrow_forward
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