In a nuclear research laboratory, a proton moves in a particle accelerator through a magnetic field of intensity 0.229 T at a speed of 3.2 × 107 m/s. The charge of a proton is 1.60218 × 10−19 C. A. If the proton is moving perpendicular to the field, what force acts on it? B. If the proton of mass 1.67262 × 10−27 kg continues to move in a direction that is consistently perpendicular to the field, what is the radius of curvature of its path?.

An electron encounters an E and B fields.B field is given by B = 0.1 j T.Electron experiences a force F = (9.6 x 10^-14 i – 9.6 x 10^-14 k)Find the electric field encountered by the electron. The velocity of the electron isv = 5 x 10^6 i m/s.

A particle with charge 9.49 x 10^-6 C moves at 1.86 x 10^6 m/s through a magnetic field of strength 2.95 T. The angle between the particle s velocity and the magnetic field direction is 48.3 degrees and the particle undergoes an acceleration of 17.4 m/s^2. What is the particle s mass?     2.23 kg     8.7 kg     15.7 kg     22.6 kg

(d) Would the electron undergo the same acceleration? O Yes O No

A laboratory electromagnet produces a magnetic field of magnitude 1.56 T. A proton moves through this field with a speed of 6.54 ✕ 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. N(b) What is the magnitude of the maximum acceleration of the proton? m/s2(c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (Assume that the electron is moving in the same direction as the proton.) YesNo     Explain. This answer has not been graded yet. (d) Would the electron undergo the same acceleration? YesNo     Explain.

A particle with charge 8.11 x 10^-6 C moves at 4.75 x 10^6 m/s through a magnetic field of strength 4.14 T. The angle between the particle s velocity and the magnetic field direction is 55.1 degrees and the particle undergoes an acceleration of 7.7 m/s^2. What is the particle s mass?     9.2 kg   16.99 kg   3.9 kg   5.4 kg