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College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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
Transcribed Image Text:A circular loop made from a flexible,
conducting wire is shrinking. Its radius as a
function of time is T Toe
Toe-t. The loop is
perpendicular to a steady, uniform magnetic
field B.

Transcribed Image Text:Find an expression for the induced in the loop at time t.
Express your answer in terms of the variables ro, B, t, B, and appropriate
constants.
{(t) =
Submit
WEI ΑΣΦΑ 1
Request Answer
?
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- A proton has a velocity of 1.1X10^2 m/s î +1.8X10^2 m/s ĵ and is located in the z=0 plane at x=3.4m, y=3.6m at some time t=T. Find the magnetic field in the z=0 plane at the following at x=1.9m, y=1.9m.arrow_forwardA particle with a mass of 5.00 x 10-16 kg and a charge of 21.0 nC starts from rest, is accelerated through a potential difference AV, and is fired from a small source in a region containing a uniform, constant magnetic field of magnitude 0.600 T. The particle's velocity is perpendicular to the magnetic field lines. The circular orbit of the particle as it returns to the location of the source encloses a magnetic flux of 15.0 µWb. (a) Calculate the particle's speed. m/s (b) Calculate the potential difference through which the particle was accelerated inside the source. Varrow_forwardA magnetic dipole with a dipole moment of magnitude 0.0306 J/T is released from rest in a uniform magnetic field of magnitude 57.6 mT. The rotation of the dipole due to the magnetic force on it is unimpeded. When the dipole rotates through the orientation where its dipole moment is aligned with the magnetic field, its kinetic energy is 0.573 mJ. (a) What is the initial angle between the dipole moment and the magnetic field? (b) What is the angle when the dipole is next (momentarily) at rest?arrow_forward
- A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.27 m. The normal to the plane of the loop is parallel to a constant magnetic field (φ = 0˚) of magnitude 0.87 T. What is the change ΔΦ in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?arrow_forwardA loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.22 m. The normal to the plane of the loop is parallel to a constant magnetic field (φ = 0˚) of magnitude 0.90 T. What is the change ΔΦ in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?arrow_forwardA flat, 132 turn current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 7.47×10−4 m2, and the angle between its magnetic dipole moment and the field is 44.9∘. Find the strength B of the magnetic field that causes a torque of 1.99×10−5 N⋅m to act on the loop when a current of 0.00327 A flows in it. ?= Tarrow_forward
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