A circuit board is cooled by passing cool air through a channelDetermine the maximum total power of the electronic components.Taking k = 0.0255ı W/m."C, v= 1.562x10 m/s, Pr = 0.7296.•p = 1.184 kg/mH= 2.325 kg/m.sC,=1007 J/kg."CAns : 24.7 kWSercAir15°CL-20 cmAir channel2 m 14 m4 m's

Answered: Image /qna-images/answer/77c9346a-c56a-46ad-a72d-170fc8a348fe.jpg

A circuit board is cooled by passing cool air through a channel Determine the maximum total power of the electronic components. Taking k = 0.02551 W/m."C, v= 1.562x10* m/s , Pr = 0.7296. P - 1.184 kg/m C,=1007 J/kg."C , p= 2.325 kg/m.s Ans : 24.7 kW

A circuit board is cooled by passing cool air through a channel Determine the maximum total power of the electronic components. Taking k = 0.02551 W/m."C, v= 1.562x10* m/s , Pr = 0.7296. P - 1.184 kg/m C,=1007 J/kg."C , p= 2.325 kg/m.s Ans : 24.7 kW

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

A circuit board is cooled by passing cool air through a channel
Determine the maximum total power of the electronic components.
Taking k = 0.0255ı W/m."C, v= 1.562x10 m/s, Pr = 0.7296.
•p = 1.184 kg/m
H= 2.325 kg/m.s
C,=1007 J/kg."C
Ans : 24.7 kW
Serc
Air
15°C
L-20 cm
Air channel
2 m 14 m
4 m's

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