R Value: Wall: 0.961m2k/w Floor: 0.676m2k/w Roof: 0.7465m2k/w In a table format show with calculations and research how much money you can save by installing a 115mm layer of insulation (R2.9) in your walls, floor and ceiling over a 5 and 10 year period. Consider the capital costs. Hint: State the current R value of each component. Convert to U value. Calculate new R value of each component (walls, floor and ceiling). Convert to U value. Use Q(W)=A*(change in U)*temperature change. Determine price for installation of new insulation. Determine price saved based on less heat loss through each component separately, then add all values together, and calculate per 5 years and per 10 years. Present all of this information in a table. You do not need to draw any diagrams, simply add the R value in series with your current components R values. Assume the energy cost is 25 cents kW

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter1: Basic Modes Of Heat Transfer
Section: Chapter Questions
Problem 1.23P: Using the information in Problem 1.22, estimate the ambient air temperature that could cause...
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R Value:

Wall: 0.961m2k/w

Floor: 0.676m2k/w

Roof: 0.7465m2k/w

In a table format show with calculations and research how much money you can save by installing a 115mm layer of insulation (R2.9) in your walls, floor and ceiling over a 5 and 10 year period. Consider the capital costs. Hint: State the current R value of each component. Convert to U value. Calculate new R value of each component (walls, floor and ceiling). Convert to U value. Use Q(W)=A*(change in U)*temperature change. Determine price for installation of new insulation. Determine price saved based on less heat loss through each component separately, then add all values together, and calculate per 5 years and per 10 years. Present all of this information in a table. You do not need to draw any diagrams, simply add the R value in series with your current components R values.

Assume the energy cost is 25 cents kWh

 

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