A chemical reaction is run in which the usual yield is 70. A new process has been devised that should improve the yield. The claim is that it produces better yields more than 90% of the time. Let p be the probability of an increased yeild. The new process is tested 65 times. Let X denote the number or trials in which the yeild exceeds the 70 threshold. Is the normal approximation appropriate for this problem? If we agree to accept the claim(new process produces better yeilds more than 90% of the time) as true if X is at least 62 what is the probability that we accept the claim as true assuming p is equal to .9? How does the probability of seeing X equal at least 62 change if p is auctally only .85? How does this change if p is auctally .95?

A person's level of blood glucose and diabetes are closely related. Let x be a random variablemeasured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a12-hour fast, the random variable x will have a distribution that is approximately normal withmean μ = 84 and standard deviation of σ = 26 What is the probability that, for an adult after a12-hour fast, x is less than 81? Group of answer choices   0.546 0.454 0.023 0.273 0.227

Captopril is a drug designed to lower systolic blood pressure. When Subjects were tested with this drug, their systolic blood pressure readings (in mm Hg) were measured before and after the drug was taken, with the results below.  Use the Wilcoxon signed ranks test to see if there is sufficient evidence to support the claim that captopril is effective in lowering systolic blood pressure. State the null and alternative hypothesis. The test statistic. The critical value, your decision and conclusion.   Subject 1 2 3 4 5 6 7 8 9 10 11 12 Before 200 174 198 170 179 182 193 209 185 155 169 210 After 191 170 177 167 159 151 176 183 159 145 146 177

Suppose you had obtained a test statistic of 2.45 (this is incorrect). What would the P-value be? Draw a conclusion based on a = 0.01. Select one: O a. 0.01 < P-value < 0.02, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O b. 0.005 < P-value < 0.01, we fail to reject Ho and do not have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O c. 0.01 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet for 6 weeks is not the same for men and women. O d. 0.005 < P-value < 0.02, we reject Ho and have sufficient evidence to conclude that the mean difference in LDL from switching from an omnivorous to a plant-based diet…