A ball is hanging from a cord of negligible weight. A secondary ball with the same weight as the first ball is measured 3m above the hanging ball, and just touching the cord, is released from rest and gains its velocity before striking the hanging ball. If the effect of friction is negligible, and the impact is perfectly elastic, compute the... a) the magnitude of the velocity of the secondary ball in terms of its velocity before contact; b) the direction of the velocity of the secondary ball in terms of its velocity before contact

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Homework Statement:: A ball is hanging from a cord of negligible weight. A
secondary ball with the same weight as the first ball
is measured 3m above the hanging ball, and just
touching the cord, is released from rest and gains its
velocity before striking the hanging ball. If the effect
of friction is negligible, and the impact is perfectly
elastic, compute the...
a) the magnitude of the velocity of the secondary
ball in terms of its velocity before contact;
b) the direction of the velocity of the secondary ball
in terms of its velocity before contact
V^2=u^2 +2gh
v= sqrt(2x9.81x3)
v=7.67m/s
a) 7.67m/s
cos theta = 1
or theta = 90 degree
b) along 90 degrees with vertical line
however, this computation is for after collision. how can i compute for the
magnitude and direction of the velocity of the secondary ball in terms of its
velocity before contact?
Transcribed Image Text:Homework Statement:: A ball is hanging from a cord of negligible weight. A secondary ball with the same weight as the first ball is measured 3m above the hanging ball, and just touching the cord, is released from rest and gains its velocity before striking the hanging ball. If the effect of friction is negligible, and the impact is perfectly elastic, compute the... a) the magnitude of the velocity of the secondary ball in terms of its velocity before contact; b) the direction of the velocity of the secondary ball in terms of its velocity before contact V^2=u^2 +2gh v= sqrt(2x9.81x3) v=7.67m/s a) 7.67m/s cos theta = 1 or theta = 90 degree b) along 90 degrees with vertical line however, this computation is for after collision. how can i compute for the magnitude and direction of the velocity of the secondary ball in terms of its velocity before contact?
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