A cannon of mass 6.13 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 74.5-kg shell horizontally with an initial velocity of 590 m/s. Suppose the cannon is then unbolted from the earth, and no external force hinders its recoil. What would be the velocity of a shell fired from this loose cannon? (Hint: In both cases assume that the burning gunpowder imparts the same kinetic energy to the system.) Number i Units

A cannon of mass 6.13 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 74.5-kg shell horizontally with an initial velocity of 590 m/s. Suppose the cannon is then unbolted from the earth, and no external force hinders its recoil. What would be the velocity of a shell fired from this loose cannon? (Hint: In both cases assume that the burning gunpowder imparts the same kinetic energy to the system.) Number i Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A bullet weighing 6.00 g is fired horizontally at a speed of 458 m/s into a wooden block weighing 1.00 kg. (Note: The block is resting on a frictionless horizontal surface). Find how fast the block will be moving if the bullet becomes embedded in the block and find out how much thermal energy was generated during the collision.
You fire a bullet at a ballistic pendulum. The large block of wood has a mass M2 = 3 kg, and the bullet has a mass of m1 = 35 g. The bullet completely penetrates the wood and emerges with a speed of vf = 80 m/s. The wood, as part of a pendulum, swings up to a maximum height of h = 11 cm. (a) Determine the speed of the block of wood after the bullet has passed through it. m/s(b) What is the speed of the bullet just before it hits the block? m/s(c) If the pendulum length is 0.8 m, what angle does the pendulum string make with the vertical when it reaches the top of its swing? degrees
Starting with an initial speed of 4.37 m/s at a height of 0.353 m, a 1.34-kg ball swings downward and strikes a 5.08-kg ball that is at rest, as the drawing shows. (a) Using the principle of conservation of mechanical energy, find the speed of the 1.34-kg ball just before impact. (b) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 1.34-kg ball just after the collision. (c) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 5.08-kg ball just after the collision. (d) How high does the 1.34-kg ball swing after the collision, ignoring air resistance? (e) How high does the 5.08-kg ball swing after the collision, ignoring air resistance? (a) Number (b) Number i (c) Number (d) Number i (e) Number Units Units Units Units Units <
A woodblock of mass Mw = 200 g is projected from the ground at a speed v0 = 35 m/s and at an angle, θ0 = 50º. When at height h = 24 m the woodblock was hit by a bullet of mass Mb = 25 g which was moving at vb = 220 m/s and at an angle θb = 70º. After the collision, the bullet embedded itself in the block and move together and land at point A on the ground. Then they move on the ground that has a coefficient of kinetic friction µk = 0.5 and starts to compress a horizontal spring at point B. The distance between point A and B is 18 m and the spring constant k = 3×10^2 N/m. The right end of the spring is fixed, and all motions are confined in x-y plane. (a) Was the collision between the wood block and the bullet elastic or inelastic? Explain quantitively. (b) Find the maximum height from the ground the block with the bullet reached. (c) How far is point A from the launch point of the woodblock? (d) Calculate the velocity at which the block-bullet system lands at point A. What…
You have just planted a sturdy 2-m-tall palm tree in your front lawn for your mother’s birthday. Your brother kicks a 500g ball, which hits the top of the tree at a speed of 5 m/s and stays in contact with it for 10 ms. The ball falls to the ground near the base of the tree and the recoil of the tree is minimal. (a) What is the force on the tree? (b) The length of the sturdy section of the root is only 20 cm. Furthermore, the soil around the roots is loose and we can assume that an effective force is applied at the tip of the 20 cm length. What is the effective force exerted by the end of the tip of the root to keep the tree from toppling? Assume the tree will be uprooted rather than bend. (c) What could you have done to ensure that the tree does not uproot easily?
**27. ssm A cannon of mass 5.80 × 10° kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires an 85.0-kg shell horizontally with an initial velocity of +551 m/s. Suppose the cannon is then unbolted from the earth, and no external force hinders its recoil. What would be the velocity of an identical shell fired by this loose can- non? (Hint: In both cases assume that the burning gunpowder imparts the same kinetic energy to the system.)
In a ballistic pendulum experiment, a small marble is fired into a cup attached to the end of a pendulum. If the mass of the marble is 0.0315 kg and the mass of the pendulum is 0.250 kg, how high ℎ will the pendulum swing if the marble has an initial speed of 5.65 m/s? Assume that the mass of the pendulum is concentrated at its end so that linear momentum is conserved during this collision.
A bullet of mass m = 8.00 g is fired into a block of mass M = 240 a that is initially at rest at the edge of a table of height h = 1.00 m (see figure below). The bullet remains in the block, and after the impact the block lands d = 1.50 m from the bottom of the table. Determine the initial speed of the bullet. Use the given information to find the velocity of the block after collision with the bullet and then use conservation of momentum to find the initial speed of the bullet. m/s Need Help? Read It Master It Submit Answer
. If collision between the block and the incline is completely elastic, then the vertical (upward) component of the velocity of the block at point B, immediately after it strikes the second incline is (a) √√30 m/s (b) √15 m/s (c) zero (d) -√15 m/s
answer is vf= 1.0 m/s.
A baseball has a mass of 0.140 kg, and it is pitched towards home plate at a speed of 48.0 m/s. Assume that the ball is pitched horizontally and that the ball is hit horizontally back in the opposite direction. If the bat exerts an average force of 9100 N for 2.80 ms, what is the final speed of the ball in m/s?
Ball A (ma = 1.200 kg) strikes ball B (mg = 1.200 kg) which is initially hanging from an extensible cord. If the initial velocity of ball A is va1 = 0.900 m/s at an angle of 60° from the vertical and assuming perfectly elastic impact, answer the following questions: 60° VA1 B