College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- In the figure, a force P acts on a block weighing 45.0 N. The block is initially at rest on a plane inclined at angle = 18.0° to the horizontal. The positive direction of the x axis is up the plane. The coefficients of friction between block and plane are μ = 0.540 and Uk = 0.340. In unit-vector notation, what is the frictional force on the block from the plane when Pis (a) (-5.30 N)î, (b) (-8.10 N)î, and (c) (-15.1 N)? (a) Number i (b) Number i (c) Number i i+ i+ i i i+ i j Units j Units j Unitsarrow_forwardBesides the gravitational force, a 2.90-kg object is subjected to one other constant force. The object starts from rest and in 1.20 s experiences a displacement of (4.30î − 3.30ĵ) m, where the direction of ĵ is the upward vertical direction. Determine the other force. (Express your answer in vector form.)arrow_forwardA block of mass m = 0.5 kg is kicked so that it slides up a ramp inclined at an angle θ = 30°. At the bottom of the ramp, the block has speed v0 = 4.0 m/s. There is a coefficient of kinetic friction between the block and ramp µK = 0.18. (a) How far up the ramp does the block slide? (b) Assume that the block comes to rest and does not slide back down the ramp. What must be the minimum coefficient of static friction between the block and ramp?arrow_forward
- David throws a 50 kg cart down a ramp with an initial speed of vi = 6 m/s. The ramp is at an angle of 20◦, and the coefficient of kinetic friction between the cart and the ramp is µk = 0.25. Additionally, the coefficient of static friction is µs = 0.55. How much time does it take to reach Ryan who is 10 m away? Assume that the cart slides and doesn’t roll.arrow_forwardA ball with mass 0.1 kg is thrown upward with initial velocity 5 m/s from the roof of a building 60 m high. Assume there is a force due to |v| air resistance of magnitude directed opposite to the velocity, where 30 the velocity v is measured in m/s. NOTE: Use g=9.8 m/s² as the acceleration due to gravity. Round your answers to 2 decimal places. a) Find the maximum height above the ground that the ball reaches. Height: m b) Find the time that the ball hits the ground. Time: seconds c) Use a graphing utility to plot the graphs of velocity and position versus time.arrow_forwardThe elevator car, including passengers, has a mass of 1800 kg. Each floor of the building is separated by 4 m (i.e., the ground floor is at 0 m, the 1st floor is at 4 m, the 2nd floor is at 8 m, etc.) and the top floor is the 10th floor. The elevator goes up from the ground floor, accelerates at a constant rate until it reaches the 1st floor at a speed of 1 m/s. It then maintains a constant speed, before decelerating (again at a constant rate) back to rest from the 9th to the 10th floor. a. Assuming that friction and drag forces are negligible, what is the maximum power output required for the elevator motor? b. How much work is done by the tension force (in the cable that pulls the elevator car up) from the ground floor to the 1st floor? From the 1st floor to the 9th floor? From the 9th floor to the 10th floor? c. How much work is done by the gravitational force from the ground floor to the 1st floor? From the 1st floor to the 9th floor? From the 9th floor to the 10th floor?arrow_forward
- An object with mass m = 34 kg is pushed with 452 N of force to be moved across a distance of 4.6 m on a surface with friction. Initially the object is moving at vi = 0.82 m/s and after being moved across 4.6 m, the final speed is 2.5 m/s. What is the magnitude of the frictional force acting on the object in the unit of N?arrow_forwardIn each my sections of MCEG 1101 (PO1 & P02), a student was asked to toss a tennis ball in front of the screen upon which a grid was projected. Based on my slow-motion video recording of the ball tossed in Section P01, the following data was generated (also see uploaded Excel file "tennis ball toss trajectory"). x (grid units) 1 2 3 4 5 6 verti cal position, y (ft) 4 3.5 2.5 2 Based on these data, a parabolic trendline was developed, as shown in the plot below: 1.5 1 0.5 819 0 7 y (grid units) 0 3 5.3 6.5 6.7 5.8 4 0.9 0.5 1 x(ft) 0.55 1.1 1.65 2.2 2.75 3.3 3.85 4.4 Tennis Ball Toss Data from MCEG 1101-P01 y(ft) 0 1.5 1.65 2.915 3.575 3.685 3.19 2.2 0.495 y = -0.9307x² + 4.7619x - 2.3925 R² = 0.999 2.5 2 3.5 horizontal position, x (ft) 3 4 4.5 5arrow_forward
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