A 500 [g] particle has velocity vx= −2.0 [m/s] at t= 0 [s]. Force Fx = (4 − t^2) [N] is exerted on the particle between t= 0 [s] and t= 2 [s]. What is the particle’s velocity at t= 2 [s] ?

A particle moves in the horizontal xy plane. A variable force acts on the particle with expression (in newtons) given by F =(4.10y+3.10)ȷ^, where y is in meters. Assume that even the particle's trajectory is a straight line from the position (in meters) r0=2.80ı^ +2.30ȷ^ to the position (in meters) rf=2.80ı^ +6.30ȷ^. Calculate the work done by this trajectory force and its de in joules, with three digits answers.   ** only numbers in the answer **

Imagine a skydiver with a mass of m jumping out of an airplane at an altitude of h. As the skydiver descends, they experience two forces: air resistance and gravity. The force of air resistance varies with time and is described by the following function, where t is the time in seconds since t e skydiver has jumped: vec 2 (F)(t) = (0.5t)ha (x) + (0.11 +0.3t)hat(y) a) Create a air free body diagrar for the skydiver at t = 2 seconds. b) - What is the net for e acting on the skydiver at t = 2 seconds? c) What i the magnitude of the acceleration of the skydiver at t = 2 seconds? Imagine a skydiver with a mass of m jumping out of an airplane at an altitude of h. As the skydiver descends, they experience two forces: air resistance and gravity. The force of air resistance varies with time and is described by the following function, where t is the time in seconds since the skydiver has jumped: Fair (t) = (0.5t)2 + (0.12 + 0.3t)ŷ a) Create a free-body diagram for the skydiver at t = 2 seconds.…

(2.2 m/s)î + (-7.8 m/s)j. Two of the forces are F = (1.5 N)i + (3.8 N)i + (-2.0 N) an Three forces act on a particle that moves with unchanging velocity v = F:= (-4,6 N)i + (3.8 N); + (-22 N)ê. What is the third force?