A 4-mF capacitor has the terminal voltage of 50 V, .. t<0 V = Ae 100t -600t + Be V, t20 If the capacitor has initial current of 2 A, find: a. The constants A and B b. Energy stored in the capacitor at t=0, c. Capacitor current for t> 0. A = Blank 1 B = Blank 2 W = Blank 3 i = Blank 4
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- Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?Please draw the problem and answer, thank you. A capacitor is made of 2 rectangular metal plates with side length of 3 cm x 6 cm separated by a distance of 2.36 cm with water in between the plates. The capacitor has a voltage of 110 v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?A parallel plate capacitor has an electrode area of 100 mm2 , with spacing of 0.1 mm between the electrodes. The dielectric between the plates is air with a permittivity of 8.85*10-12 F/m. The voltage on the capacitor is 100 V. The stored energy in the capacitor is ?
- a. Show how you would connect all five capacitors to get a maximum capacitance and find the maximum capacitance in terms of C. b. Show how you would connect all five capacitors to get a minimum capacitance and find the minimum capacitance in terms of C.When the capacitor is charged current flows on either side of the capacitor. Do electrons cross the gap to allow the current on the other side of the circuit?(b) Is charging and discharging time of capacitor equal in a theoretical RC circuit?Plase explain your answer by using relating formula.A 10-9.F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 3× 1018 2, on a humid day, the resistance is 6 × 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? ... On the dry day, it will take seconds.
- At 0-, no currrent flows through the capacitors because they are open, how did you combine the capacitors for the voltage divider since it is the capacitance value and not reactance, is it right? Can we just combine the capacitance value? Please explain. I did not understand..Determine the total capacitance, total charge, individual voltage drop and charges across each capacitor. Use two decimal places for your answer. Put your answer for the individual voltage and charge for each capacitor in a table for faster checking. Thank you! Here are the values for the capacitors: C1 = 55 C6 = 50 C2 = 25 C7 = 17 C3 = 49 C8 = 44 C4 = 22 C9 = 53 C5 = 45 C10 = 44A 20-ohm resistor and a capacitor are connected in series with a battery of 60 volts. At t = 0, there is no charge on the capacitor. Find the capacitance if the current at t = 5 seconds is 3/e^s amperes. Ans. 0.05 Farads
- Ask NVC M Gmail YouTube Maps Google bily 6. in (A) 21 2. 4. 5. Consider the following figure that shows the current in an inductor of 5 H. Find the voltage across the inductor at t= 3.5 second. otherwise 125 V -12.5 V 25 V 75V +++A capacitor is made of 2 rectangular metal plates with side length of 3cmx6cm separated by a distance of 2.36 with water in between the plates. The capacitor has a voltage of 110v and is not connected to a battery. Calculate the capacitance. What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? What is the new voltage? What is the charge on each plate?1) First part of the question: Two identical capacitors are connected in parallel and charged with a 20-V power supply as shown in the figure on the left. After the charges on the capacitors have reached their final values, the charge on each capacitor is 10 µC. Then the power supply is disconnected and a dielectric with K = 4 is inserted to fill the space between the plates of one of the capacitors. a) Find now the charge on the capacitor with dielectric. Give your answer in microcoulombs. Qo = 10 µC Qo = 10 µC| Q2 =? ► V = 20 V Battery