2. The expression for capacitor voltage in an RC circuit (assuming no initial charge) when DC voltage is applied is ve(t) = V,(1-e-(1/RC)). Assume V, = 10 V, C= 50 µF, and R 100 2. Calculate capacitor voltage when t : %3D 1*RC 5*RC 10*RC 3. The voltage across an inductor when a DC voltage is switched on is v, (t) = Ve-t/L/R). Assume V, 10 V, L = 1 mH, and R 12. Find the voltage across the capacitor at t=: %3D 0 ms 1 ms 10 ms 4. Derivation: Consider the equation for wa: wa = V(1/LC) – (R/2L)2

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter8: Basic Electric Motors
Section: Chapter Questions
Problem 25RQ: List the five capacitor replacement rules.
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2. The expression for capacitor voltage in an RC circuit (assuming no initial
charge) when DC voltage is applied is vc(t) = V(1- e-(t/RC)). Assume V,
= 10 V, C = 50 µF, and R 100 N. Calculate capacitor voltage when t =:
1*RC
5*RC
10*RC
3. The voltage across an inductor when a DC voltage is switched on is vi(t) =
Ve-(t/L/R). Assume V, = 10 V, L= 1 mH, and R = 1 N. Find the voltage
across the capacitor at t= :
0 ms
1 ms
10 ms
4. Derivation: Consider the equation for wa:
Wa =
(1/LC)- (R/2L)²
Oscillation will occur only when this expression is a real number (not an
imaginary number). Solving, we see that the expression is a real number
when (1/LC) > (R/2L)2. If C=0.01µF capacitance and L = 10 mH, what
is the largest value of R for this condition to be true? You will use this result
in the lab.
Transcribed Image Text:2. The expression for capacitor voltage in an RC circuit (assuming no initial charge) when DC voltage is applied is vc(t) = V(1- e-(t/RC)). Assume V, = 10 V, C = 50 µF, and R 100 N. Calculate capacitor voltage when t =: 1*RC 5*RC 10*RC 3. The voltage across an inductor when a DC voltage is switched on is vi(t) = Ve-(t/L/R). Assume V, = 10 V, L= 1 mH, and R = 1 N. Find the voltage across the capacitor at t= : 0 ms 1 ms 10 ms 4. Derivation: Consider the equation for wa: Wa = (1/LC)- (R/2L)² Oscillation will occur only when this expression is a real number (not an imaginary number). Solving, we see that the expression is a real number when (1/LC) > (R/2L)2. If C=0.01µF capacitance and L = 10 mH, what is the largest value of R for this condition to be true? You will use this result in the lab.
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