A 3.7 × 10−4 M solution of compound X has an absorbance of 0.5342 when measured at 740 nm. Assuming a pathlength of 1 cm, calculate compound X’s molar absorptivity.
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Q: A 3.7 x 10-4M solution of compound X has an absorbance of 0.5342 when calculate compound X's molar…
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A 3.7 × 10−4 M solution of compound X has an absorbance of 0.5342 when measured at 740 nm. Assuming a pathlength of 1 cm, calculate compound X’s molar absorptivity.
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- A) Phenol Red is a weakly acidic dye which is yellow in the HA form and red in the A form. What concentration of Phenol Red is required to obtain an absorbance of 0.50 at 550 nm at pH 7.8? Note: ε550 of A = 2.5 x 104 M-1 cm-1; ε550 of HA = 0; pKa = 7.8. B) What would the absorbance of the solution in part (a) be if the pH was 8.8?Suggest a possible structure for Compound X.Compounds A and B absorb in the UV region. Compound A exhibits an absorption maximum at 267 nm (a=157) and a trailing shoulder at 312 nm (a=12.6). Compound B has an absorption maximum at 312 nm (a=186) and does not absorb at 267 nm. A solution containing the two compounds exhibits absorbances (using a 1-cm cell) of 0.726 and 0.544 at 267 and 312 nm, respectively. What is the concentration of B in mg/L? 2.16 x 10-3 mg/L 4.62 x 10-3 mg/L 5.02 x 10-2 mg/L 2.61 x 10-3 mg/L -3 4.26 x 10¬ mg/L 3.46 x 10-8 mg/L
- Based on this IR spectrum and 1H NMR spectrum and the given chemical formula is C9H10O2, what would be the chemical structure of the compound? Please give a full analysis of the NMR spectra for given compound.Phthalimide is insoluble in water. Will phthalimide dissolve in aqueous NaOH?Compound X was dissolved in a 5-mL volumetric flask. A 1.00-mL aliquot of the compound was placed in a 10-mL volumetric flask and diluted to the mark. The solution was read in a UV-Vis spectrophotometer and an absorbance of 0.427 in a 1.000-cm cuvette was observed at 340 nm. Solve the following question. Data for Compound X:Molecular mass = 292.16 g/molMolar absorptivity (ɛ) at 340 nm= 6130 M -1 cm -1 a. Calculate the concentration of compound X in the cuvette. b. How many milligrams of compound X were used to make the 5-mL solution?
- Compound X was dissolved in a 5-mL volumetric flask. A 1.00-mL aliquot of the compound was placed in a 10-mL volumetric flask and diluted to the mark. The solution was read in a UV-Vis spectrophotometer and an absorbance of 0.427 in a 1.000-cm cuvette was observed at 340 nm. Solve the following question. Data for Compound X:Molecular mass = 292.16 g/molMolar absorptivity (ɛ) at 340 nm= 6130 M -1 cm -1 1. What was the concentration of compound X in the 5-mL flask?Amine A is a liquid at room temperature and pressure. When vaporised, 0.202g of the amine produces 72.0 cm3 of gas at 1.00 × 105Pa and 100 °C. The 13C NMR spectrum of amine A has 3 peaks. Determine the molecular formula of A and suggest a possible structure for amine A.Show the reaction and equilibrium expression for the basic dissociation of trimethylamine. Given that the Ka = 1.58 x 10-10 for trimethyl ammonium ion, use this to calculate the equilibrium constant for the basic dissociation of trimethyl amine. If the concentration of trimethylamine is 0.10 M, what is the pH of the solution?
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