A 3 kg particle starts from rest at x = 0 and moves under the influence of a single force F= 10 + 5x - 3x2, where F, is in newtons and x is in meters. Calculate the work done by the force as the particle moves from x = 0 to x = 2 m

A single conservative force acts on the a 5.0 kg object.  The equation Fx = 2x + 4 describes the force, where x is in meters.  As the object moves along the x axis from x = 1.0 m to x = 5.0 m calculate the work done by this force.

Problem 6: Two forces act on an object. F₁ = (10î – 7ĵ) N and F₂ = −15î N. = The object travels from ₁ = +4 m, both on the x axis. -4 m to ₂: = a) What is the work done by F₁? b) What is the work done by F₂? c) What is the net work done? Problem 7: A strap on a suitcase is angled at 25° above horizontal and is used to pull the suitcase a distance of 250 m through an airport. The weight of the suitcase is 50 N. The resistive force of friction on the suitcase is 14 N. The strap applies 20 N of force to the suitcase. a) How much work does gravity do on the suitcase? b) How much work is done on the suitcase by the strap? c) How much work does friction do on the suitcase? d) The suitcase began at rest, how fast is it moving after traveling this distance? Problem 8: A block of mass m = 500 g slides down an incline that has an inclination angle of 30° with the horizontal. The inclined surface has coefficient of kinetic friction µK = 0.4. The block moves 3 m down the incline. a) How much work…

The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 0.250 m.) Find the work done by the force as the particle moves across the following distances. (a) from x = 0 m tox = 2.00 m(b) from x = 2.00 m to x = 3.00 m(c) from x = 0 m to x = 3.00 m

A particle moves in the x-axis from x = 12.8 m to x = 23.7 m under the influence of a force   where F is expressed in newtons and x is expressed in meters. Use numerical integration to determine the total work done by the force during the displacement. In the networks there are Various calculators for integrals are available.

The graph shows the xx component of a force that acts on an object that moves on the x axis. The vertical spacing between adjacent grid lines is 4.93N, while the horizontal spacing between adjacent grid lines is 1.0m.  What is the work, in joules, done by the force as the object moves from x=4m to x=5m?

A force = (8x + 7y ) N acts on an object as if moves in the x direction from the origin to x = 7.00 m. Find the work done on the object by the force.

(a) A force F= (2x1 + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the /F. F. dr done by the force on the object (in J). x-direction from the origin to x = 4.63 m. Find the work W = J (b) What If? Find the work W = (4.63 m, 4.63 m) along a straight-line path making an angle of 45.0° with the positive x-axis. J F. dr done by the force on the object (in J) if it moves from the origin to Is the work done by this force dependent on the path taken between the initial and final points? dependent independent

The force required to compress a non-standard spring varies as the spring is compressed, as shown by the plot of force vs displacement. Distances are x1 = 10, x2 = 25 cm, x3 = 55 cm, and x4=75cm, and the forces are F1 = 110 N and F2 = -60N. Calculate the work done in Joules, on the spring as it is compressed from origin to point x4.

The force on a particle is directed along an x axis and given by F = Fo(x/xo - 1) where x is in meters and Fis in Newtons. If Fo= 2.1 N and xo = 2.0 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.