A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of (Figure 1). Figure 0.01 ΩΣ + 12 V 050 ΩΣ Jumpers Good battery 8V Dead battery 1 of 1 > 0.05 ΩΣ Starter motor ▼ Part A How much current could the good battery alone drive through the starter motor? Express your answer with the appropriate units. I = Part B Submit Request Answer μА I= Value Submit How much current is the dead battery alone able to drive through the starter motor? Express your answer with the appropriate units. μA Value Units Request Answer ? Units ?

The batteries shown in the circuit in the figure (Figure 1) have negligibly small internal resistances. Figure 10.0 V 30.0 Ω < 1 of 1 20.0 Ω 5.00 V Find the current through the 20.0 resistor. Express your answer with the appropriate units. I20.02= 0.250 A Ω Submit ✓ Correct Part C Previous Answers Find the current through the 10.0 V battery. Express your answer with the appropriate units. I10.0 V = Submit μA Value Request Answer Ć Units ?

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The circuit in the figure below contains two resistors, R₁ = 1.7 k and R₂ = 2.7 km, and two capacitors, C₁ = 2.3 μF and C₂ = 3.1 μF, connected to a battery with emf E = 100 V. If there are no charges on the capacitors before switch S is closed, determine the charges 9₁ and 92 on capacitors C₁ and C₂, respectively, as functions of time, after the switch is closed. Hint: First reconstruct the circuit so that it becomes a simple RC circuit containing a single resistor and single capacitor in series, connected to the battery, and then determine the total charged a stored in the circuit. (Use the given values for R₁, R₂, C₁, C₂, and E. Use the following as necessary: t. Do not include any units in your response.) 91 = 92= μC μc R₁ www R₂ S + d E C₂

You charge an initially uncharged 63.1 mF capacitor through a 21.9 Q resistor by means of a 9.00 V battery having negligible internal resistance. Find the time constant r of the circuit. What is the charge Q on the capacitor 2.01 time constants after the circuit is closed? Q = C What is the charge Q, after a long amount of time has passed? Oo = C

A 16.0 µF Capacitor is charged to Qo. It is then connected in a simple loop circuit with a 265 Q resistor (and nothing else). How much time does it take for the capacitor to reach 25% of its initial charge? O 5.88 ms O 9.03 ms O 4.24 ms O 1.22 ms

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In the figure the current in resistance 6 is ig = 1.48 A and the resistances are R1 = R2 = R3 = 2.23 Q, R4 = 16.5 Q, R5 = 8.09 Q, and Ré = 4.10 Q. What is the emf of the ideal battery? R R2 R, Rg R4 tatatat Number i Units

In the figure the current in resistance 6 is i6 = 1.48 A and the resistances are R₁ = R₂ = R3 = 2.37 02, R4 = 15.10, R5 = 8.11 Q2, and R6 = 3.16 Q. What is the emf of the ideal battery? Number i E www R₁ Units www R3 www R₂ R₁ www R₂ R₁

An RC circuit includes a basic switch, two voltmeters and an ammeter. Initially the capacitor is either partially or fully charged, and the switch is open. Data collection begins, and then the switch is moved to position "b" allowing the capacitor to begin discharging. Part 1: Which graph best represents the magnitude of the voltage measured across the capacitor by the voltmeter labeled Vc? O O t Part (a) Which graph best represents the charge on the positive plate of the capacitor as a function of time? O O O Vo O a o .b Part 2: Which graph best represents the magnitude of the voltage measured across the resistor by the voltmeter labeled VR? O Part (b) Which graph best represents the current measured with the ammeter as a function of time? O R t A I O Vc