The following circuit has an ideal battery of potential difference 15.16V and R1 has a resistance of 3.15Ω and R2 has a resistance of 9.17Ω. The capacitor has a capacitance of 6.06pF. What is the current through R2 after this circuit has been hooked up for a long time?
The following circuit has an ideal battery of potential difference 15.16V and R1 has a resistance of 3.15Ω and R2 has a resistance of 9.17Ω. The capacitor has a capacitance of 6.06pF. What is the current through R2 after this circuit has been hooked up for a long time?
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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The following circuit has an ideal battery of potential difference 15.16V and R1 has a resistance of 3.15Ω and R2 has a resistance of 9.17Ω. The capacitor has a capacitance of 6.06pF. What is the current through R2 after this circuit has been hooked up for a long time?
Expert Solution
Step 1
When circuit is hooked up for a long time then capacitor get fully charged and steady state will be reached.i.e., no current will flow through the arm containing capacitor therefore only consider the resistors.
Resistors are connected in series hence current through both resistor will be same.
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