You connect an initially uncharged 6.40 μF capacitor in series with a 5.00 MΩ resistor and a battery with emf 12.0 V. After letting the capacitor charge for 51.0 s, you disconnect it from this circuit and connect it in series to an open switch and a 6.00 MΩ resistor.   A) Find the charge on the capacitor when you disconnect it from the first circuit. B) Find the charge on the capacitor 70.0 ss after you close the switch in the second circuit.

At time t=0, the switch is moved to position A and remains there for 2.00 seconds. Then the switch is moved to position B. Assume the battery and ammeter are ideal and the resistance of the wires is negligible. a) Find the charge on the capacitor after the switch was in position A for 2.00 seconds. R = 27.5 KQ m (Α + C = 47.0 μF (initially uncharged) Switch position A E 12.0 V b) Find the current through the ammeter after the switch has been in position B for 1.00 second. c) How long does it take (after the switch is moved to position B) for the charge on the capacitor to decrease to 53.0 μC?

c) A 6 V battery B has an internal resistance of 1 2. It is connected in parallel with a 5 resistor R5 and this combination is in series (and parallel) with a resistor R of RS. i) Find the voltage VR across R for the three cases, when R = 0, when R = ∞, and when R = 1.25 2. 2 ii) Using your results from (i) or otherwise, show that the parallel combination of B and R5 is equivalent to a battery of voltage Veq with internal resistance Req, and find the values of Veg and Req.

B4. and the battery has a voltage V = 12 V. (a) Find the equivalent capacitance of the network. C (b) Find the total energy stored in the network.