Fill in table one and two please!! 93157*= shouldbe equal11. If the impulse momentum theorem is correct, the change in the momentum will be equal to theimpulse for each trial. Experimental measurements error along with friction and shifting of thetrack or force sensors will keep the two from being the same. One way to compare the two is tofind their percent different. Do this for the change in momentumAp=mv-mv₁Oand the impulse calculation12. Fill in Table #112TrialI = FAt*Table 1:Impulse[FFdt = FAtInitial momentum(N·s)Final momentum(N·s)(N·s)*Change inmomentum Ap(N·s)Velocity trial 1: -1.060 m/s (initial)Part 2:(velocity).-0.033mls (final):Trial 2 - 1.023mls (in)Repeat the experiment using a double rubber band. :-0.009mis (final)TrialImpulse[ Fdt = FAt(N·s)LTable 2:Initial momentum Final momentum(N·s)(N·s)Part 3:AVelocity 2: -1.014 m/s (i): -0.085 mis (f)0.860ml sci: 0.031 mis(f)Change inmomentum Ap(N·s)tralMoni

Answered: Image /qna-images/answer/ad4201a0-9fff-469f-9c15-8fa53b785042.jpg

Answered: 93157 *= should be equal 11. If the…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter9: Momentum And Its Conservation

Section: Chapter Questions

Problem 83A

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ANSWERS must be in 3 decimal places A 50 kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3 m/s. 1. What was the impulse acting on the mass? 2. What is the final momentum of the mass? 3. What was the force acting on the mass?
A ball of mass 0.470 kgkg moving east (+x+xdirection) with a speed of 3.84 m/sm/s collides head-on with a 0.235 kgkg ball at rest. Assume that the collision is perfectly elastic. 1.What is be the speed of the 0.470-kgkg ball after the collision? Express your answer to three significant figures and include the appropriate units. 2. What is be the direction of the velocity of the 0.470-kgkg ball after the collision? East or west? 3.What is the speed of the 0.235-kgkg ball after the collision? Express your answer to three significant figures and include the appropriate units. 4.What is the direction of the velocity of 0.235-kgkg ball after the collision? East or west?
Which is the formula that describes the magnitude of impulse on an object? A. impulse = mass x acceleration B. impulse = mass x change in velocity C. impulse = mass * (velocity)2 x 0.5 D. impulse = mass x velocity
Donald went off to play a game of billiards. He hit the 0.63 kg white ball which began to move at8.2 m/s. Afterward, it struck a stationary 8 ball of the same mass.a. Illustrate a diagram of the moment of collision.b. Compute for the momentum before the collision of the white ball.c. Compute for the momentum before the collision of the 9 ball.d. What are the velocities of the two balls after the collision?Donald went off to play a game of billiards. He hit the 0.63 kg white ball which began to move at 8.2 m/s. Afterward, it struck a stationary 8 ball of the same mass. a. Illustrate a diagram of the moment of collision. b. Compute for the momentum before the collision of the white ball. c. Compute for the momentum before the collision of the 9 ball. d. What are the velocities of the two balls after the collision?
Learning Goal: To understand the relationship between force, impulse, and momentum. The effect of a net force EF acting on an object is related both to the force and to the total time the force acts on the object. The physical quantity impulse J is a measure of both these effects. For a constant net force, the impulse is given by J = FAt. The impulse is a vector pointing in the same direction as the force vector. The units of J are N. sor kg · m/s. Recall that when a net force acts on an object, the object will accelerate, causing a change in its velocity. Hence the chiect's momentum in- mail will also change. The Figure F (N) L 12,000 0.0007 1 of 1 t (s) In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70 × 10-³ s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball? Enter your answer numerically in newton…
Help Hide smartermarks.com 7. Use the following number association: 1 = vector 2= scalar Identify the following as a vector or scalar quantity, by matching it with the appropriate number. Momentum is a quantity. (a) Kinetic energy is a Impulse is a Time is a The values for a, b, c, and d are and Your answer: 0000 Use the following information to answer the next two questions An atom of thorium, initially at rest, decays into two particles with one particle having a mass 24 times greater than the other particle. Immediately after the thorium atom decays, the larger particle moves to the left with a velocity of 2.70x104 m/s. 8. The magnitude of the velocity of the particle with less mass, expressed in scientific notation, is a.bc x 10d m/s. The values of a, b, c and d are. and (Record your answer in the numerical-response section below.) Your answer: 0000 9. The system can be considered because EPIC O GAMES MacBook Air quantity. (b) quantity. (c) quantity. (d) i tv 32 Smarter Marks ::…
per during the collision? 5. A ball of mass 0.80 kg moving initially at 8.0 m's has a head-on collision with a 0.40 kg ball that is at rest. If the collision is perfectly elastik, what is the velocity of each ball after the collision?
A 5.0 kg mass moving with a velocity of 8.0 m/s East has an impulse applied to it which causes its velocity to change to 20.0 m/s East. a. Find the impulse of the mass. b. Find the force if the impulse was applied for 3.0s.
p = mv J = Ft Ft = m Av Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s. N
Please show steps and equations used for each problem
What are the units for momentum. what are the units for impulse
what equations will we use?

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