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A block with mass m and a velocity v10 collides with a block M at rest. At some time later after the collision the two masses have velocities v1 and v2. No other information is given about the surface on which the blocks are sliding. Which of the following is true? The system consists of the two blocks. a) the mechanical energy of the system is conserved, but the momentum of the system is not b) the momentum of the system is conserved, but the mechanical energy of the system is not conserved c) neither the momentum nor the mechanical energy of the system need be conserved

A 0.430-kg blue bead slides on a frictionless, curved wire, starting from rest at point O in the figure below, where h = 1.50 m. At point O, the blue bead collides elastically with a 0.640-kg green bead at rest. Find the maximum height the green bead rises as it moves up the wire.

Cons Block 1, of mass m1 = 2.90 kg , moves along a frictionless air track with speed vị with block 2, of mass m2 = 57.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) 13.0 m/s. It collides %3D Part A Part B Part C What the change AK = Kfinal – Kiniti. in the two-block system's kinetic energy due the collision? Express your answer numerically in joules. • View Available Hint(s) Figure 1 of 1 HV ΑΣφ ? Before collision: m2 m1 AK = 1 Submit After collision: Provide Feedback 1 2.

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The ball only loses energy during the collisions. Energy is conserved between collisions. We will denote E the total energy of the ball after the first collision, E2 the total energy of the ball after the second collision, and in general, En will represent the total energy of the ball after the nth collision. Consider the floor to be the reference for zero potential energy. Question 4 a. Find the coefficient of restitution in terms of the ball's kinetic energy just before and just after the nth collision (n > 2). b. If the coefficient of restitution is e = 0, what does that imply about the energy lost during the collision? c. If the coefficient of restitution is e = 1, what does that imply about the energy lost during the collision?

A 25.0 g bullet traveling horizontally at 500 m/s strikes a 0.750 kg block of wood that is balanced on the edge of a table 0.800 m above the floor. If the bullet embeds itself into the block, then (a) how fast is the bullet and block combination moving immediately after the collision and (b) how far horizontally from the edge of the table will the bullet and block combination hit the floor? Include a diagram of the situation as needed.

How would you find the velocity of the cue ball after the collision? (Please include magnitude and direction). Also, would this be an elastic or inelastic collision?