9. A troublesome reaction that is responsible in part for acid rain is SO3 + H₂O → H₂SO4 Rate data have been determined at a particular temperature for the reaction in which all reactants and products are gases. Trial Run Initial [SO] Initial [H₂O] 0.15 M 0.20 M 0.15 M 0.40 M 0.30 M 0.20 M 4 0.30 M 0.40 M The rate-law expression is rate = k[SO] 1 2 3 Initial Rate (M-s¹) 0.150 0.600 0.300 1.20 [H₂O]
9. A troublesome reaction that is responsible in part for acid rain is SO3 + H₂O → H₂SO4 Rate data have been determined at a particular temperature for the reaction in which all reactants and products are gases. Trial Run Initial [SO] Initial [H₂O] 0.15 M 0.20 M 0.15 M 0.40 M 0.30 M 0.20 M 4 0.30 M 0.40 M The rate-law expression is rate = k[SO] 1 2 3 Initial Rate (M-s¹) 0.150 0.600 0.300 1.20 [H₂O]
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![9. A troublesome reaction that is responsible in part for acid rain is SO3 + H₂O → H₂SO4
Rate data have been determined at a particular temperature for the reaction in which all reactants
and products are gases.
Trial Run
Initial [SO]
Initial [H₂O]
1
0.15 M
0.20 M
2
0.15 M
0.40 M
3
0.30 M
0.20 M
4
0.30 M
0.40 M
The rate-law expression is rate = k[SO]
Initial Rate (M-s¹)
0.150
0.600
0.300
1.20
[H₂O]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4dc380c-a82f-4308-8d95-1a09bead5fa9%2F302b4f97-6445-49e0-987e-cba332e69c09%2Fhi65lcq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9. A troublesome reaction that is responsible in part for acid rain is SO3 + H₂O → H₂SO4
Rate data have been determined at a particular temperature for the reaction in which all reactants
and products are gases.
Trial Run
Initial [SO]
Initial [H₂O]
1
0.15 M
0.20 M
2
0.15 M
0.40 M
3
0.30 M
0.20 M
4
0.30 M
0.40 M
The rate-law expression is rate = k[SO]
Initial Rate (M-s¹)
0.150
0.600
0.300
1.20
[H₂O]
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