*7-16. Determine the resultant internal loadings on the cross section through point C. Assume the reactions at the supports A and B are vertical. 6 kN 3KN/m IC 1.5 m 15 m- 0.5 m0.5 m

Determine the resultant internal loadings at cross sections at points E and F on the assembly. 1.25 kN/m D E 0.5 m 0.5 m 0.5 m B 1 m -1.5 m 2 m

Provide the correct exponents and distances to make the singularity function given valid for the beam shown. V₁ = 8 kN, V2 = 7 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. ATATV3 -V3- (mm) O The singularity functions are q = R₁(x)ª − v₁(x − P)ª − v₂(x − Q)¹ + R₂(x − R)ª V = R₁ – v₁(x – D)³ − v2(x − E)³ + R2(x – F)³ M = R₁x – v₁(x – G)ª − v₂(x − H)C + R₂(x − 1)C From the given singularity functions the exponents aro (1) (2)

The beam supports the distributed load shown. Determine theresultant loadings acting on the cross-section e-e at point D.Assume the reactions at the supports A and B are vertical.