MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Suppose the lengths of human pregnancies are normally distributed with μ = 266 days and o 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with μ = 266 days and o=16 days. The area to the right of X = 290 is 0.0668. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The proportion of human pregnancies that last less than OB. The proportion of human pregnancies that last more than days is days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts more than OB. The probability that a randomly selected human pregnancy lasts less than days is days is or more than and days…arrow_forwardA normal distribution has a mean of u= 80 with o= 12. Find the following proportions with the given score: (X < 74). Be sure to illustrate the normal distribution and shade in the region in question.arrow_forwardAt a certain high school, every freshman has his or her height The freshman boys have a mean height of 65.2 inches and a standard deviation of 3.2 inches. The freshman girls have a mean height of 63.5 inches and a standard deviation of 2.7 inches. The proportion of of freshman girls has heights between 60 to 65 inches is 0.6133. What is the interpretation of this normal density area? (i) The proportion of freshman having heights between 60 to 65 inches is 0.6133 (ii) The probability that a randomly selected freshman girl have heights between 60 to 65 inches is 0.6133 or 61.33% Oboth (i) and (ii) are correct We can not interpret the given area..arrow_forward
- Compute the range and sample standard deviation for strength of the concrete (in psi). 3920, 4070, 3500, 3100, 2930, 3870, 4070, 4010 The range is S= psi. psi (Round to one decimal place as needed.)arrow_forwardCompute the range and sample standard deviation for strength of the concrete (in psi). 3910, 4090, 3500, 3100, 2940, 3830, 4090, 4040arrow_forwardAssume that a sample is used to estimate a population mean μμ. Find the margin of error that corresponds to a sample of size 16 with a mean of 68.3 and a standard deviation of 17.9 at a confidence level of 99%.Report the margin of error accurate to one decimal place because the sample statistics are presented with this accuracy.E=arrow_forward
- Please I need this answered in 30 min.arrow_forwardSuppose the lengths of human pregnancies are normally distributed with p = 266 days and o = 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with u = 266 days and o = 16 days. The area to the right of X= 285 is 0.1175. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The proportion of human pregnancies that last more than days is 266 285 O B. The proportion pregnancies that last less thar days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than days is B. The probability that a randomly selected human pregnancy lasts more than days isarrow_forwardThe lifetime of a Michelin defender tire (in thousands of miles) is normally distributed with mean μ = 41 and standard deviation σ = 7. What proportion of Michelin tires have lifetimes between 35 and 47 thousand miles?arrow_forward
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