Please Answer and explain #18 J mu p vulue THat čorresponds Tð 2 = -1.32?P(ZC -1.32)=0.093917. What is the z-score that corresponds to P = 0.9131?standard divation 0=1PSZLZ )=131P(Z Q L)P= 09131 s1.3618. If the mean is 225 and the standard deviation is 28 for a normally distributed variable, what is the x vathat corresponds to a z = -0.93?-6.93 =(x-て2う)125X= 225 - (0.93)(23) F198.9¢%3D%3D19. If the mean is 19 and a standard deviation is 3.7 for a normally distributed variable, what is the z-sc-represent the x value of 14.9?2= x-M「リ- 4-19%3Dこ2 scort =20. Find the z-score that corresponds to P15?2.=-1.0364|-1.03 G4

Name: Please Answer and explain #18 J mu p vulue THat čorresponds Tð 2 = -1.
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Please Answer and explain #18 J mu p vulue THat čorresponds Tð 2 = -1.32?P(ZC -1.32)=0.093917. What is the z-score that corresponds to P = 0.9131?standard divation 0=1PSZLZ )=131P(Z Q L)P= 09131 s1.3618. If the mean is 225 and the standard deviation