6. Calculate enthalpy change of the reaction using enthalpy of formation values. Hint: Used Balanced equation. tenoge doneli _C3H8(g) + T43m p O₂ (g) → AH values in kJ/mol _CO₂(g) + H₂O(1) C3H8(g) = -103.8; CO₂ (g) = -393.5; H₂O (1) = -285.8 lanab ai show 30 1 2008 to seando verso lampt

10. Calculate the standard enthalpy of formation of N₂O5 from the following data: kJ mol kJ 2NO(g) + O₂(g) →2NO₂(g) 4NO2(g) + O₂(g)→2N205(g) N₂(g) + O₂(g) →2NO(g) 4,H☺ = -114.1 = -110.2- 'mol kJ mol AH AH = + 180.5,

2 E6L14(s) + 19 A2(g) → 12 MA2(g) + 7 L₂A(g) AH = 1300 kJ/molrxn 21. What is the enthalpy of formation, AH, for the substance E6L14 shown in the reaction above? AH (kJ/mol) ??? со How Substance E6L14(S) A₂(g) De MA₂(g) L₂A (g) 0 100 50 B

Find the enthapy change for the reaction below in kJ .                   4NH3(g)  + 5O2(g) --> 4NO(g) + 6H2O(g)     ΔH= ?    Given :  (NH3(g)) = -46.1,         (NO(g)) =  + 90.3 kJ/mol   and        (H2O(g)) = -241.8 kJ/mol.

Enthalpy changes for the following reactions can be determined experimentally: ) - A2 (g) + 3 C2 (g) 4AC3 (g) + 5B2 (g) 4AB (g) + 6C2B (g) C, (g) + 1/2 B2 (g) C2B (g) AH - -→2AC3 (g) AH --175 kJ/mol ΔΗ. -162kJ/mol. --1,176 kU/mol Use these values to determine the enthalpy change for this reaction: 1/2 A2 (g) + 1/2 B2 (g) → AB (g) AH = ? Enter your answer in kJ/mol to 0 decimal places and without units.

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2HBr(g) + Cl₂(g) → 2HCl(g) + Br₂(g) AH (HBr(g)) = -36.3 kJ/mol AH (Cl₂ (9)) = 0.0 kJ/mol AH (HCl(g)) = -92.3 kJ/mol AH (Br₂ (9)) = 30.9 kJ/mol AH rxn = kJ

The combustion of 0.1566 g benzoic acid increases the temperature of a bomb calorimeter by 2.51°C. Calculate the heat capacity of this calorimeter. (The energy released by combustion of benzoic acid is 26.42 kJ/g.) Heat capacity = kJ/°C A 0.2195-g sample of vanillin (Cg H3 O3) is then burned in the same calorimeter, and the temperature increases by 3.21°C. What is the energy of combustion per gram of vanillin? Energy = kJ/g Per mole of vanillin? Energy = kJ/mol

A student runs two experiments with a constant-volume "bomb" calorimeter containing 1100. g of water (see sketch at right). thermometer stirrer First, a 5.500 g tablet of benzoic acid (C,H,CO, H) is put into the "bomb" and burned completely in an excess of water oxygen. (Benzoic acid is known to have a heat of combustion of 26.454 kJ/g.) The temperature of the water is observed insulation to rise from 15.00 °C to 42.56 °C over a time of 10.3 minutes. Next, 5.720 g of acetaldehyde (C2H,O} are put into the "bomb" and similarly completely burned in an excess of oxygen. This time the temperature of the water rises from 15.00 °C to 40.53 °C. chemical reaction "bomb" Use this information, and any other information you need from the ALEKS Data resource, to answer the questions below about this reaction: A "bomb" calorimeter. 2C,H,0(g) + 50, (g) 4CO, (g) + 4H,0 (g) Be sure any of your answers that are calculated from measured data are rounded to the correct number of significant digits. Note…

The balanced thermochemical equation for the combustion of exactly one mole of propane is: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O(l) ΔH = -2220 kJ/mol What is the enthalpy change for the reaction: 1.5 CO2 (g) + 2 H2O(l)  → 0.5 C3H8 (g) + 2.5 O2 (g) ΔH = ?

How much heat is produced when 0.480 mol of methane is burned under standard conditions. Enthalpy of combustion of methane = -891 kJ/mol. - A) -891 kJ B 428 kJ -222 kJ -644 kJ -428 kJ