5. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced on the bolt or the tube. The temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross- sectional area of the bolt is 0.08 sq. inch and the cross-sectional area of the tube of 0.25 sq. inch. For steel: E = 30 x 106 psi, coefficient of thermal expansion = 6.5 x 10-6/°F For aluminum: E = 10 x 106 psi, coefficient of thermal expansion = 13.0 x 10-6/°F %3D a. Find the thermal deformation (in inches) of the bolt. b. Find the thermal deformation (in inches) of the aluminum tube. c. Find the stress (in psi) induced in the bolt by the temperature change. d. Find the stress (in psi) induced in the aluminum tube by the temperature change.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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5. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just
touches the end of the tube. No stress is introduced on the bolt or the tube. The
temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross-
sectional area of the bolt is 0.08 sq. inch and the cross-sectional area of the tube of 0.25
sq. inch.
For steel: E = 30 x 106 psi, coefficient of thermal expansion = 6.5 x 10-6/°F
For aluminum: E = 10 x 106 psi, coefficient of thermal expansion = 13.0 x 10-6/°F
a. Find the thermal deformation (in inches) of the bolt.
b. Find the thermal deformation (in inches) of the aluminum tube.
c. Find the stress (in psi) induced in the bolt by the temperature change.
d. Find the stress (in psi) induced in the aluminum tube by the temperature change.
Transcribed Image Text:5. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced on the bolt or the tube. The temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross- sectional area of the bolt is 0.08 sq. inch and the cross-sectional area of the tube of 0.25 sq. inch. For steel: E = 30 x 106 psi, coefficient of thermal expansion = 6.5 x 10-6/°F For aluminum: E = 10 x 106 psi, coefficient of thermal expansion = 13.0 x 10-6/°F a. Find the thermal deformation (in inches) of the bolt. b. Find the thermal deformation (in inches) of the aluminum tube. c. Find the stress (in psi) induced in the bolt by the temperature change. d. Find the stress (in psi) induced in the aluminum tube by the temperature change.
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