5 kN/m | 2 kN B C A MA -5 mm settlement 4 m- -2 m– RA RB PROBLEM 10.4-18

Answer should be : Mo : 189.3 lb ft, O = 18.5 lb at 248 from positive axes

Please writte Answer by hand Thank You

A beam, which is fixed at one end, is acted upon by a distributed load (the curve is a continuous cubic curve) as shown in the figure. Calculate the reactions at the support. Include proper signs (with right, up and counterclockwise assumed to be positive for X, Y and the moment) 300 N/m y = kx3 %3D 300 N/m 4 m 3 m Ry (in N) = ? R,(in N) = ? M* (in N) =?

2. For the simply supported beam shown below, a. Find reactions at A and D b. Sketch the V-M diagrams. IA ت am E IB am 2m 2m F 14 N 10 KN C am TA

A continuous beam supports loads as shown in the image. Determine the support reactions using the three-moment method. Consider that the stiffness of the beam is constant throughout.

4. The box beam is made of an elastic-perfectly plastic material for which the yield 250 MPa. Draw the residual stress distribution in the beam after the elastic-plastic moment, Mep = 548.5 kNm, is applied and then released. It can be shown that under the applied moment, the flanges (260 mm × 30 mm) yield, while the webs (2 x 200mm x 30mm) show linear elastic behavior. The moment of inertia and plastic section modulus of the section are given below: I = 247.48 x 106 mm4; Z, = 2394000 mm³ stress oy = y 30 mm 30 mm 200 mm 200 mm 30 mm 30 mm