1. A beam of length L = 10 ft is supported by a fixed (cantilever) support at O. Determine the reactions at O when the beam supports these loads: A = 10 lb, B = 300 lb-ft and C = 10 lb, as shown. Determine the magnitude and direction of the moment at the fixed support at O. Determine the magnitude and direction of the reaction force at O. MA = 4 * 10 lb (CCW) MC = 10ft * 10 sin (45) (CCW) MB = 300 lb-ft (CW) Sum M) = 40 + 100(sin 45) - 300 Fy= 10 + 10 sin45 Fx = 10 sin 45 Ry = (-10-10sin45) Rx = -10 (sin 45) O A B 45.0⁰

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Answer should be : Mo : 189.3 lb ft, O = 18.5 lb at 248 from positive axes
1. A beam of length L = 10 ft is supported by a fixed (cantilever) support at O. Determine the
reactions at O when the beam supports these loads: A = 10 lb, B = 300 lb-ft and C = 10 lb, as
shown. Determine the magnitude and direction of the moment at the fixed support at O.
Determine the magnitude and direction of the reaction force at O.
MA = 4 * 10 lb (CCW)
MC = 10ft* 10 sin (45) (CCW)
MB = 300 lb-ft (CW)
Sum M) = 40 + 100(sin 45) - 300
Fy = 10 + 10 sin45
Fx = 10 sin 45
Ry = (-10-10sin45)
Rx = -10 (sin 45)
4.00 ft
3.00 ft
B
3.00 ft
45.0⁰
Transcribed Image Text:1. A beam of length L = 10 ft is supported by a fixed (cantilever) support at O. Determine the reactions at O when the beam supports these loads: A = 10 lb, B = 300 lb-ft and C = 10 lb, as shown. Determine the magnitude and direction of the moment at the fixed support at O. Determine the magnitude and direction of the reaction force at O. MA = 4 * 10 lb (CCW) MC = 10ft* 10 sin (45) (CCW) MB = 300 lb-ft (CW) Sum M) = 40 + 100(sin 45) - 300 Fy = 10 + 10 sin45 Fx = 10 sin 45 Ry = (-10-10sin45) Rx = -10 (sin 45) 4.00 ft 3.00 ft B 3.00 ft 45.0⁰
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