### Calculating Support Reactions for a Loaded BeamIn this example, we will calculate the support reactions at points \(A\) and \(B\) for the loaded beam.#### Given Data:- Force \(P = 143 \text{ lb}\)- Distributed Load \(w = 92 \text{ lb/ft}\)- Distance \(a = 3.2 \text{ ft}\)- Distance \(b = 7.0 \text{ ft}\)#### Diagram Explanation:The diagram provided illustrates a beam supported at two points, \(A\) (fixed support) and \(B\) (roller support). The following elements are depicted:- **Support at A:** This support can provide reactions in both the horizontal (\(A_x\)) and vertical (\(A_y\)) directions.- **Support at B:** This is a roller support that provides a vertical reaction (\(B_y\)).- **Point Load \(P\)** applied vertically downward at a distance \(a\) from support \(A\).- **Distributed Load \(w\):** The load varies linearly across the span from point \(A\) to point \(B\).- **Coordinates:** \(x\) represents the horizontal axis, while \(y\) represents the vertical axis.#### Calculation Objective:We need to compute the reactions at the supports \(A_x\), \(A_y\), and \(B_y\).#### Calculation Steps:1. **Sum of Horizontal Forces:** \[ \Sigma F_x = 0 \] \[ A_x = 0 \] 2. **Sum of Vertical Forces:** \[ \Sigma F_y = 0 \] \[ A_y + B_y - P - w \times (a + b) = 0 \] 3. **Moment Around Point A:** \[ \Sigma M_A = 0 \] \[ -P \times a - \left( \frac{w \times (a + b) \times (a + b/2)}{2} \right) + B_y \times (a + b) = 0 \]By solving these equations, the values for \(A_y\) and \(B_y\) can be determined. Insert these computed values:#### Answers:- \( A_x = \)- \( A_y = \)-

Answered: Image /qna-images/answer/3a2cb088-d692-45df-b7e8-6db44b13e449.jpg

Answered: Calculate the support reactions at A…

Calculate the support reactions at A and B for the loaded beam. Assume P = 143 lb, w = 92 lb/ft, a = 3.2 ft, and b = 7.0 ft. L A _a. P b W B

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: 4) The 500-kg uniform beam is subjected to the three external loads shown. Compute the reactions at…

A: According to the given data W=500x9.81=4905N=4.905 kN at distance=1.2+1.8+1.82=2.4m from O The…

Q: Problem 1. The beam is loaded by the centered point force P. The supports on both sides are full…

A: Here we will apply equilibrium conditions.

Q: 3. A simply supported beam of length 8 m carries point loads of 4 kN, 10 kN and 7 kN at 1.5 m, 2.5 m…

Q: Calculate the support reactions at A and B for the loaded beam. Assume P = 51 lb, w = 82 lb/ft, a =…

Q: Find the support reactions, draw the free-body diagram of the beams that shows the reactions and the…

Q: Determine the support reactions of the beam shown. 3 kip/ft B A C -6 ft 4.5 ft- 4.5 ft

Q: A simply supported beam with a length of 5 m is carrying a uniform load of 10 KN/m throughout the…

Q: 2. For the beam shown: a. Draw the free-body diagram of the beam. b. Determine the reactions at the…

Q: For the given beam with shown loàding, determine the reacCtion at the roller support. 20 kips/ft B A

A: Given Load, P = 20 kips/ft Length, L = 8 ft Find Reaction at roller support, R2

Q: The 9.75 m long beam is simply supported at A and B as shown below with a uniformly distributed load…

A: Here, we know that for a uniformly distributed load we can replace that load as an concentrated load…

Q: Mo B ROPS

Q: For the beam shown, determine the reactions at A, B and C. At B is a pin, C is a roller and at A is…

Q: please help! 15 minutes left! upvote will be given! NO EXPLANATION NEEDED! STATICS OF RIGID BODIES.…

A: Given as,

Q: Please write steps clearly Determine the reactions at A and B for the beams loaded as shown. Beam…

A: To find: The reaction at A and B. FBD.: The free body diagram shown below: The vertical force at C…

Q: Calculate the reaction at the supports for the beams shown below A -3 m- 10 KN 10 kN/m -3 m- B

A: Calculate the reaction at the supports for the beams shown below,

Q: 2. For the beam shown: a. Draw the free-body diagram of the beam. b. Determine the reactions at the…

A: Mechanical Equilibrium: A body is said to be in mechanical equilibrium if it satisfies the following…

Q: A A) RA= 1 50 KN 1m 1.5m B) RA= 45 KN/m 40 KN/m 6.00 m KN, R₂ = 3.00 m KN, R₂ = 20 275 KN 1m 4.00 m…

A: find the reactions on the supports.

Q: 3. For the shown beam, determine the reactions at support A 33 A 30 kip-ft 2 kip/ft -32 12 kips 5…

Q: Using the relationship method, sketch and label the phear force and bending moment diagram for the…

Q: Calculate the vertical component of reaction support at point A (i.e., Ay) for the loaded beam shown…

A: Given:

Q: Calculate the reactions at A and B for the beam shown. 24 kN 24 kN 12 kN/m D E 1,8 m 0.6 m 0.6 m 0.6…

Q: Find the support reactions, draw the free-body diagram of the beams that shows the reactions and the…

Q: Determine reaction at fixed support

A: Consider load at free end is P Using equilibrium condition : ∑FX=0RAX=0∑FY=0RAY-P=0RAY=P

Q: Don't skip any steps. The answer should include free body diagram.

A: To determine the reactions at the beam supports for the given loading, we need to analyze the system…

Q: Problem I. The beam has a loose fit built-in support at B which allows the end of the beam to rotate…

A: According to terms and conditions of bartleby we can only provide upto 3rd part . Thank you ! Given…

Q: Find the moment reaction at C (Mc), given that W 43 KN. Neglect the weights of the members as well…

Q: Determine the reactions at the supports for the beam shown in Fig. 3.18(a).

A: Let the roller support be labelled as A and hinged support be B.Consider reaction at A be RA and…

Q: The beam supports two loads, w;(x) = 20x² + 100, where w, is in lb/ft and x is in ft, and a linearly…

A: Given Data: The load w1=20x2+100 and a span of 0'<x3' The linearly varying load is from 280 lb…

Concept explainers

Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

Question

### Calculating Support Reactions for a Loaded Beam

In this example, we will calculate the support reactions at points \(A\) and \(B\) for the loaded beam.

#### Given Data:
- Force \(P = 143 \text{ lb}\)
- Distributed Load \(w = 92 \text{ lb/ft}\)
- Distance \(a = 3.2 \text{ ft}\)
- Distance \(b = 7.0 \text{ ft}\)

#### Diagram Explanation:
The diagram provided illustrates a beam supported at two points, \(A\) (fixed support) and \(B\) (roller support). The following elements are depicted:

- **Support at A:** This support can provide reactions in both the horizontal (\(A_x\)) and vertical (\(A_y\)) directions.
- **Support at B:** This is a roller support that provides a vertical reaction (\(B_y\)).
- **Point Load \(P\)** applied vertically downward at a distance \(a\) from support \(A\).
- **Distributed Load \(w\):** The load varies linearly across the span from point \(A\) to point \(B\).
- **Coordinates:** \(x\) represents the horizontal axis, while \(y\) represents the vertical axis.

#### Calculation Objective:
We need to compute the reactions at the supports \(A_x\), \(A_y\), and \(B_y\).

#### Calculation Steps:
1. **Sum of Horizontal Forces:**
\[ \Sigma F_x = 0 \]
\[ A_x = 0 \]

2. **Sum of Vertical Forces:**
\[ \Sigma F_y = 0 \]
\[ A_y + B_y - P - w \times (a + b) = 0 \]

3. **Moment Around Point A:**
\[ \Sigma M_A = 0 \]
\[ -P \times a - \left( \frac{w \times (a + b) \times (a + b/2)}{2} \right) + B_y \times (a + b) = 0 \]

By solving these equations, the values for \(A_y\) and \(B_y\) can be determined. Insert these computed values:

#### Answers:
- \( A_x = \)
- \( A_y = \)
-

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given Information

Step 2: Calculation

Step 3: Calculation

Solution

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

kal, la The beam AB weighs 1200 N supports a distributed load as shown in fig. * ?Determine the reaction in A and B 250 N/m X- 12 m Ay= 1600 N and By= 2600 N O Ay= 2600 N and By= 1600 N O Ay= 2100 N and By= 2100 N O Ay= 480 N and By= 660 N O
Determine the vertical reaction at A in kN for the beam shown below, where: L1=3 m L2=2 m Lg-2 m 91-2 KN/m by0.0"Ly m c-0.2'L1 m P1=14 AN a1-0.3L1 m P2=5 kN Assume upward is positive and give your answer to one decimal place D. L
Determine the reactions at the supports A and B of the beam shown below. -4ft - 15 kip 4 ft 4 ft B
Find the support reactions, draw the free-body diagram of the beams that shows the reactions and the equivalent loadings of the beams. Show the computation where w0 = 12 lb/in, w1 = 170 lb/ft, a = 5 ft, b = 9 ft, c = 12 ft
Answer the question quecly please
B5
Draw free-body diagrams of column AB and beam BC and joint B by passing cutting planes through the rigid frame an infinitesimal distance above support A and to the right and immediately below joint B. Evaluate the internal forces on each free body.
The beam shown below has a pin or hinge joint at B. The beam is simply supported at A. For this beam, the reaction force at point A is: 2 kip 6 kip/ft OA 36 kip O B. 12 kip OC6 kip O D.8 kip
Find the support reactions, draw the free-body diagram of the beams that shows the reactions and the equivalent loadings of the beams. Show the computation where Wo = 12 kN/m, P = 10 kN, a = 2 m, b = 2.5 m, c = 2m
3- Calculate the reactions at supports A and F of the beam shown below. 21 KN 12 kN 5m 3m 4m 4m E ES - 110 HOMEWORK # 6 DUE 10/19/21 -300lb Smooth surface AN 4'-
Please help me find the correct solution for this DISTRIBUTED LOADS problem. Thank you! ASAP!
For the beam and loading shown, determine the magnitude of the vertical reaction at A (Ib) provided that a=179, b=120 and c=6.7. Do not round off in any intermediate steps. Round off only on the final anwer expressed in 3 decimal places. a lb/ft b lb/ft: A |B c ft-