44. Wildcard Matching Hard 6 4222 P 188 Add to List O Share Given an input string ( s ) and a pattern (p), implement wildcard pattern matching with support for ?' and * where: '?' Matches any single character. ** Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). Example 1: Input: s= "aa", p Output: false Explanation: "a" does not match the entire string "aa". Example 2: Input: s= "aa", p = "*" Output: true Explanation: *' matches any sequence. Example 3: Input: s = "cb", p = "?a" Output: false

Ex: Use getline() to get a line of user input into a string. Output the line. Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. Ex: Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. BFF: best friend forever IDK: I don't know Support these abbreviations: BFF -- best friend forever IDK -- I don't know . JK -- just kidding TMI -- too much information TTYL-talk to you later 1 #include 2 // FIXME include the string Library 3 using namespace std; 4 5 int main() { 6 7 8 9 10 } /* Type your code here. */ return 0; main.cpp

Please dont copy and paste previous solutions. I checked them they are wrong.

Select all the strings that are elements of the following set: {a,b}² U{a,b}³ U {a,b}4 (b) (ba) (bbbba) ☐ (abbba) □ (abaaa) (bbabb) (bbbab) (a)

Use Java pl DataFileWords.txt: lovegentlensslovepeacelovekindnesslovepeaceunderstandingkindnessjoypeaceunderstandingfriendshipgentlenssgoodnesslovepeacegoodnesslovegentlensscontrolunderstandingunderstandinggentlensslovepeacepatiencecontrolkindnessgentlensslovepeacejoygoodnesspeacefriendshipgoodnesskindnesslovepeacegoodnesscontrolpatiencejoygentlensspatiencegentlensspatiencekindnessgoodnessjoygentlenssgentlenss

Revorse the vewels def reverse_vowels(text): Given a text string, create and return a new string constructed by finding all its vowels (for simplicity, in this problem vowels are the letters found in the string 'aeiouAEIOU') and reversing their order, while keeping all other characters exactly as they were in their original positions. However, to make the result look prettier, the capitalization of each moved vowel must be the same as that of the vowel that was originally in the target position. For example, reversing the vowels of 'Ilkka' should produce 'Alkki' instead of 'alkkI'. Applying this operation to random English sentences seems to occasionally give them a curious pseudo-Mediterranean vibe.Along with many possible other ways to perform this square dance, one straightforward way to reverse the vowels starts with collecting all vowels of text into a separate list, and initializing the result to an empty string. After that, iterate through all positions of the original text.…

1. Create a UML using the UML Template attached.  2. In this lab, you will be creating a roulette wheel. The pockets are numbered from 0 to 36.  The colors of the pockets are as follows: Pocket 0 is green.  For pockets 1 through 10, the odd-numbered pockets are red and the even-numbered pockets are black. For pockets 11 through 18, the odd-numbered pockets are black and the even-numbered pockets are red. For pockets 19 through 28, the odd-numbered pockets are red and the even-numbered pockets are black. For pockets 29 through 36, the odd-numbered pockets are black and the even-numbered pockets are red. Create a class named RoulettePocket. The class's constructor should accept a pocket number. The class should have a method named getPocketColor that returns the pocket's color, as a string.   Demonstrate the class in a program that asks the user to enter a pocket number,  and displays whether the pocket is green, red, or black. The program should display an error message if the user…

def findOccurrences(s, ch):     lst = []     for i in range(0, len(s)):         if a==s[i]:             lst.append(i)     return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n):     word = input("welcome!")     guesses = ''     turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word):            secrete_word = "-" * len(word)     print(" the secrete word " + secrete_word)         user_input = input("Guess a letter: ")         if user_input in word:         occurences = findOccurrences(word, user_input)         for index in occurences:             secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:]         print(secrete_word)     else:         user_input = input("Sorry that letter was not found, please try again: ")   def findOccurrences(s, ch):     return [i for i, letter in enumerate(s) if letter == ch]  *** enumerate not discussed in…

You may assume the string contains only lowercase alphabets.Reference: https://leetcode.com/problems/valid-anagram/description/"""def is_anagram(s, t):    """    :type s: str    :type t: str    :rtype: bool    """    maps = {}    mapt = {}    for i in s:        maps[i] = maps.get(i, 0) + 1    for i in t:        mapt[i] = mapt.get(i, 0) + 1    return maps == mapt

in c++ code