4.68 A half-wave rectifier circuit with a 1-k2 load oper- ates from a 120-V (rms) 60-Hz household supply through a 10-to-1 step-down transformer. It uses a silicon diode that can be modeled to have a 0.7-V drop for any current. What is the peak voltage of the rectified output? For what fraction of the cycle does the diode conduct? What is the average output voltage? What is the average current in the load?

3. It is required to design a full-wave rectifier circuit using the circuit shown below to provide an average output vol tage of10 V. find the required turns ratio of the transformer. Assume that a conducting diode has a voltage drop of0.7 V. The ac line vol tage is120 Vrms.

S-2) a) On the bridge type full wave rectifier circuit given in the figure Plot the current paths for each of the +/- alternans. b) The waveform of the Vç output voltage is given in the graphs on the side. Draw it in the blank and calculate the peak value and indicate it in the graph. c) Calculate the effective value of the output voltage. (Vç (eff) =… ..?). Note: Diodes are not ideal. VD = 0.7V.

It is required to design full-wave rectifier circuits. Consider the rectifier circuits shown in figures (a) center-tapped rectifier, (b) bridge rectifier. Assume the input voltage is from 120V(rms), 60HZ ac source. The desired peak output voltage vo is 10V. A conducting diode has a voltage drop of 0.7V. In each case, (i) Determine the required turns ratio of the transformer; (ii) Determine the required peak inverse voltage (PIV) of the diodes. D, Center tap R. D. ac line line voltage R voltage D (b) (a) Ans: (1) Turns Ratio (ii) PIV Center tapped Center tapped_ Bridge Bridge