4. The voltage for the a-phase of a balanced wye-connected source with an abc-phase- sequence is Van = 120/90° Vrms. Determine the rms line voltages for this source. ↓ V ab V bc = Vca = са
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- The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. Use Gauss-Seidel method in Matlab to analyze the system the tolerance of error is 10-3. Then anwser the questions as follows. V, = 1.05200 0.01+ j0.025 300 + j200 MVA 0.015 + j0.035 150 MW 200 +j150 MVA 0.01+ j0.03 |V = 1.03 The admittance matrix (Y_bus)? 0.02 + jo.04 0.0125 + jo.03 2.The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. ' qu V = 1.05200 0.01+ j0.025 300 + j200 MVA 3 0.015 + j0.035 150 MW 200 + j150 MVA 0.01 + j0.03 |V = 1.03 The admittance matrix (Y_bus)? The bus power in per-unit?A delta connected load with Zab=3 + j2 Ohm, Zbc=3 + j4 Ohm and Zca=2 + j3 Ohm are connected the end of a three-phase line as shown in the figure. The line impedance is 1+j2 Ohm per phase. The line is supplied from a three-phase source with line-to-line voltage of Vab=200.0/0° V rms. Taking the phase current vector lab as the reference vector, determine; (a) Line current Ia. (b) Total complex power supplied from the source. (c) Magnitude of the line-to-line voltage at the load terminal. ao- bo- Co- 1+j2 b a
- The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. ' V, = 1.05200 0.01 + jo.025 300 +j200 MVA 3 0.015+j0.035 150 MW 200 +j150 MVA 4 0.01 + j0.03 |V2 = 1.03 The admittance matrix (Y_bus)? 0.02 + jo.04 0.0125 + jo.03Draw a 3-phase wye-connected generator with transmission lines connected to a 3-phase delta-connected load. Assume the lines connecting them have an inductance of j5 per phase. The generated voltages are 120 Vrms with phase 'a' having a phase angle of 0°. The loads are 10 Ohm resistors per phase. When drawing, make sure to label all 3 phases with voltage phasors, line inductances, and load resistances.A balanced Y-connected generator with terminal voltage Vbc 5 200/08 volts is connected to a balanced-D load whose impedance is 10/408 ohms per phase. The line impedance between the source and load is 0.5/808 ohm for each phase. The generator neutral is grounded through an impedance of j5 ohms. The generator sequence impedances are given by Zg0 5 j7, Zg1 5 j15, and Zg2 5 j10 ohms. Draw the sequence networks for this system and determine the sequence components of the line currents.
- In a star connected three-phase balanced (RYB) system, the phase angle between phase voltage ( VR )and phase voltage ( VY ) phase voltage is a. 180 degree b. 120 degree c. 30 degree d. 90 degree4) A balanced delta connected load of ...+j18 ohm per phase is connected at the end of a three phase line as shown in figure. The line impedance is 1+j2 ohm per phase. The line is supplied from a three-phase source with a lie- to-line voltage of 207.85 V rms. Taking Van as reference, determine the following: a) Current in phase a. b) Total complex power supplied from the source. c) Magnitude of the line-to-line voltage at the load terminal. (Please determine the impedance value within the specified limits: 16-26 V. By considering the impedance value you determined yourself, solve the question.) ao- |V₂| bo Co- 1 +j2 Ω = 207.85 V www Figure a Jum ...+j18 n bFor a three-phase positive sequence ΔΔ-connected system, Vab=3.6∠56.0Vab=3.6∠56.0. Then VbnVbn is:
- Given: 1. 2 wye-connected loads per phase to a 3 phase power source 2. first load consists of a 55ohm resistance and a 0.05H inductance per phase 3. second load consumes 1kW and power factor of 0.7 lagging per phase 4. RMS of voltage across the loads are 220V, frequency 120Hz per phase 5. single phase equivalent is shown in the figure: Question: Give the value of reactive power per phase seen at load 2.The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load under sinusoidal-steady-state excitation. is (a) Nonzero constant (b) Zero (c) Containing double-frequency componentsIn a balanced system, the phasor sum of the line-to-line voltages and the phasor sum of the line-to-neutral voltages are always equal to zero. (a) False (b) True