4. In Drosophilia, the allele b gives black body (wild type is b+ or brown), and at a different gene locus, the allele cn gives cinnabar eyes (wild type eyes are cn+ or red.) A female which is heterozygous for both genes is testcrossed. [A testcross is a mating ma ly that is homozvgous for all recessive mutant traits. a male, homozygous for black and cinnabar.J Male: b b/cn cn In this case, the fly is Female b b+/cn cn+ The following progeny are observed: 53 brown body, red eyes 50 black body, cinnabar eyes A. Write the genotypes of each class of progeny. 451 brown body, cinnabar eyes 446 blackbody, red eyes the fomawo most common groups of progeny each bear one of the parental chromosomes from Lemale. (Remember the two parental chromosomes segregate during gamete formation.) on the two chromosomes from the female. prane two least common groups of progeny represent recombination events during meiosis. Draw which alleles are present on the recombined chromosomes. D. Calculate the percent of recombinants in this cross. between genes. Draw which alleles are This is a measure of distance Each 1% is called one map unit.

4. In Drosophilia, the allele b gives black body (wild type is b+ or brown), and at a different gene locus, the allele cn gives cinnabar eyes (wild type eyes are cn+ or red.) A female which is heterozygous for both genes is testcrossed. [A testcross is a mating ma ly that is homozvgous for all recessive mutant traits. a male, homozygous for black and cinnabar.J Male: b b/cn cn In this case, the fly is Female b b+/cn cn+ The following progeny are observed: 53 brown body, red eyes 50 black body, cinnabar eyes A. Write the genotypes of each class of progeny. 451 brown body, cinnabar eyes 446 blackbody, red eyes the fomawo most common groups of progeny each bear one of the parental chromosomes from Lemale. (Remember the two parental chromosomes segregate during gamete formation.) on the two chromosomes from the female. prane two least common groups of progeny represent recombination events during meiosis. Draw which alleles are present on the recombined chromosomes. D. Calculate the percent of recombinants in this cross. between genes. Draw which alleles are This is a measure of distance Each 1% is called one map unit.

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter13: Modern Understandings Of Inheritance

Section: Chapter Questions

Problem 2VCQ: Figure 13.4 Which of the following statements is true? Recombination of the body color and red/...

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3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?
2. Drosophila females heterozygous for three recessive x-linked markers y (yellow bodies), ct (cut wings), and m (miniature wings) were crossed to y ct m males and the following progeny were obtained. F1 Phenotype Yellow, cut, miniature Wildtype Yellow Cut, miniature miniature Number cut 60 63 20 13 Yellow, cut 15 Yellow, miniature 5 22 2 a) F1 Genotype b) Recombinant or Parental? c) SCO, DCO, or NONE? a) Fill in the table with the genotypes of each progeny type, use + to indicate wildtype/dominant traits, show separate homologues. b) In the table, identify whether each progeny type is Recombinant (R) or Parental (P). c) In the table, identify whether each progeny type results from a single crossover (SCO), a double crossover (DCO), or no crossing over (NONE). d) Diagram the parental cross, clearly indicating allelic contributions from each homologue of parental flies. Heterozygous wild-type Female Fly X Hemizygous mutant Male fly // // e) Draw the genetic map showing correct order and…
I. Male Drosophila from a true-breeding wild-typestock were irradiated with X-rays and then mated withfemales from a true-breeding stock carrying the following recessive mutations on the X chromosome:yellow body (y), crossveinless wings (cv), cut wings(ct), singed bristles (sn), and miniature wings (m).These markers are known to map in the order:y - cv - ct - sn - mMost of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and snphenotypes. When this exceptional ct sn female wasmated with a male from the true-breeding wild-typestock, twice as many females as males appearedamong the progeny.a. What is the nature of the X-ray-induced mutationpresent in the exceptional female?b. Draw the X chromosomes present in the exceptional ct sn female as they would appear duringpairing in meiosis.c. What phenotypic classes would you expect to seeamong the progeny produced by mating the exceptional ct sn female with a normal male from a truebreeding wild-type…
2. The following is a pedigree of a family in which a rare form of X-linked colorblindness is found (filled-in symbols). II 2 II 3 4 a. Label the genotypes of as many family members as the available information permits. Remember that this gene is located on the X-chromosome when writing out genotypes. b. Is the colorblindness trait recessive or dominant? Explain how you know.
Miniature wings, X in Drosophila melanogaster result from an X-linked allele that is recessive to the allele for long wings, 9 + X. Match the genotypes for each parent in the crosses. Male parent phenotye long miniature miniature 111 long long Female parent phenotype long long long miniature long m m X X Male offspring phenotypes 231 long, 250 miniature 610 long 410 long, 417 miniature 753 miniature 625 long m X Y Female offspring phenotypes 560 long 632 long 412 long, 415 miniature 761 long 630 long Answer Bank ++ X X Male parent genotype + X Y Female parent genotype + X X m 00
3. In the test cross r/+ s/+ w/+ z/+ rswz/rswz, the following offspring are obtained: X Phenotype r st w+ z r stw z Number 359 47 4 rs w z+ rs w+z+ 98 rt st w z 92 r+ s w z+ 351 r+ st w+ z 6 r+s w+ z+ a) Construct a map of the genes showing their relative distance apart. 43 b) Is there any interference in this region? Note: the listed gene order is arbitrary. Can you deduce the proper order by inspection?
8. While vermilion is X-linked and brightens the eye color, brown is an autosomal recessive mutation that darkens the eye. Flies carrying both mutations lose all pigmentation and are white-eyed. Predict the Fl and F2 results of the following crosses: a) vermilion females X brown males b) brown females X vermilion males
1. A mechanism for equalizing the expression of X-linked genes in males and females of a species. [ Choose ] Conjugation Reciprocal Crosses Transduction Binary Replication Haplotype Interference Transformation Gain of Function Mutation Allelic Series Blending Theory Dosage Compensation Rolling Circle Replication Pleiotropy Coefficient of Coincidence Reciprocal Cross Loss of Function Mutation Synaptonemal Complex Allelic Phase Allele Chiasma Law of Independent Assortment 2. A group of alleles of a gene that show a hierarchy of dominance relationship among them. [ Choose ] Conjugation Reciprocal Crosses Transduction Binary Replication…
1. The allele G for yellow stigma is completely dominant to green (g). Supposingtwo strains of autotetraploid plants are available and their genotypes are as follows:GGgg – in this plant the gene is close to the centromereGggg – in this plant the gene is far from the centromere If these two plants are crossed:a) provide the gametes that can be obtained from the two plants;b) provide the genotypic and phenotypic ratios of the offspring. 2. Consider the illustration below. Diagram the configuration you would observe at Anaphase I if crossing-over happens within the inversion. (IMAGE ATTACHED)
5. A cross between two wild-type flies gave progeny all of which were wild type. When vg e they were test crossed to flies the following results were obtained: vg e (a) 4 of the test crosses gave wild type, vestigal ebony, vestigal and ebony in a 1:1:1:1 ratio. (b) 4 of the test crosses gave all wild type. (c) 4 of the test crosses gave vestigal and wild type in a 1:1 ratio. (d) 4 of the test crosses gave ebony and wild type in a 1:1 ratio. What are the genotypes of the original pair of wild-type flies?
2. The homozygous mutant a, an allele of the albinism gene in the mouse, has a white coat and dark eyes. The homozygous mutant p has pink eyes. Mice of genotype a+/+p are testcrossed with mice homozygous for the two mutations. The progeny obtained are shown below. Calculate the recombination frequency and map distance between the two genes. Phenotype of Progeny White coat, dark eyes White coat, pink eyes Dark coat, white eyes Dark coat, pink eyes Number 240 31 34 474
2. A heterozygous (+/c) for curved wings is crossed to another heterozygous (+/c) for curved wings. Complete the F1 AND F2 generations. Express the genotypes and phenotypes for each generation. F1: +C +C +C F2: ++ +C +C P1= ++ X cc P2= ++ X cc Genotypes: Genotypes: Phenotypes: Phenotypes: