3. The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that cou result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female). ld a. Possible genotypes for Black coat:Chestnut coat: b. Possible genotypes for Trotting gait:Pacing gairi Male possible gametes: Female possible gametes: c. Male genotype d. Female genotype: e. f. Genotypic Ratio: g. Phenotypic Ratio:

3. The chestnut coat color of horses is due to a recessive gene, while the dominant allele results in black. The pacing gait is due to a recessive gene, whereas the dominant allele results in the trotting gait. Show the types of offspring that cou result from a cross of a black trotter (male), heterozygous for both genes, with a chestnut pacer (female). ld a. Possible genotypes for Black coat:Chestnut coat: b. Possible genotypes for Trotting gait:Pacing gairi Male possible gametes: Female possible gametes: c. Male genotype d. Female genotype: e. f. Genotypic Ratio: g. Phenotypic Ratio:

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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3. Black coat (B) color in Cocker Spaniels is dominant, while red coat (b) color is recessive; solid pattern (S) is dominant, while spotted (s) pattern is recessive. Create a Punnett square that shows all of the possible offspring of a solid black male (BBSs) mated to a solid red female (bbSs). Include the percentage/ratio of occurrence for each phenotype. Include the percentage/ratio of occurrence for each phenotype.
1. A cow is heterozygous for three genes (WwPp) where W-White, w-Brown, P-Polled, p-Horned. Give the phenotypic and genotypic ratio of their offspring if the cow is inter se mated. 2.A male Sahiwal (RRHH) is crossed with a female Angus (Rrhh). Where R-Red, r-Brown, H-Horned, h-polled. Give the phenotypic and genotypic ratio of their offspring.
2. In purple people eaters, one horn (H) is dominant and no horns (h) is recessive. Complete the punnett square to show the cross of two hybrid purple people eaters. Summarize the genotypes and phenotypes of the possible offspring. Possible genotypes of offspring: Possible phenotypes of offspring: www.ShellysScienceSpot.com
1. In cattle, the hornless condition (H) is dominant and the horned condition (h) is recessive. bull without horns is crossed with a cow without horns. Of the four offspring, one (1) is horn and three (3) are hornless. Using Punnett squares, determine the genotype of the parental bul and the cow.
4. Two heterozygous black pigs are mated. Show the genotypes, phenotypes, and probabilities of the offspring. What are the genotypes of the parents? Genotypes Phenotypes 5. In Holstein cattle the spotting of the coat is recessive to the solid coat color. What types of offspring might be produced by a cross between two spotted animals? Ohat are the genotypes of the parents? Genotypes Phenotypes
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
V. Two Gene Pairs (Extra Credit) 1... A. In peas, the allele for tall plants (T) is dominant over the allele for short plants (t). The allele for smooth peas (S) is dominant over the allele for wrinkled peas (s). Use this information to cross the following parents. I 1. heterozygous tall and smooth X heterozygous tall and smooth 2. heterozygous tall, wrinkled X short, wrinkled AL.
17. Three recessive traits in aardwolf (a real animal) are stripe-less (s), dwarf (d), and fluffy mane (f). A stripe-less and fluffy female aardwolf mates with a dwarf male aardwolf to produce an F1 that is all WT (has stripes, normal size, and non-fluffy mane). When an F1 is test crossed to a fully recessive aardwolf, the following F2 are produced: Stripe-less, fluffy, normal sized 89 Striped, non-fluffy, dwarf 92 Stripe-less, non-fluffy, dwarf 1 Striped, fluffy, normal sized 2 11 13 19 20
. An allele A that is not lethal when homozygous causes rats to have yellow coats. The allele R of a separate gene that assorts independently produces a black coat. Together, A and R produce a grayish coat, whereas a and r produce a white coat. A gray male is crossed with a yel-low female, and the F1 is 3 8 yellow, 3 8 gray, 1 8 black, and 1 8 white. Determine the genotypes of the parents.
1. In "Four o' Clock “plants, it's flower color is incompletely dominant. The red flowers are homozygous dominant, the white flowers are homozygous recessive, and the pink flowers are heterozygous. Show genetic crosses between the following Four O'clock parents, using the Punnett squares provided and indicate the genotypic and phenotypic % below: A. Red x white Genotypic %: Phenotypic %: B. White x Pink Genotypic %: Phenotypic %: C. Pink x Pink Genotypic %: Phenotypic %:
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratio
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio: