4. Calculate the rms value of the current waveform. i(t). 5 0 5 10 15 20 25
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A: Evaluating the average value of the above graph:
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A: Given that Alternating voltage=282.8 sin314t volts------1We have to find the a RMS voltage. (b) The…
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A: The relationship between rms and peak value is given by: V(rms) = V(peak)÷√2 Simliraly ,V(peak) =…
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A: The solution can be achieved as follows.
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Q: An alternating voltage is given by v=282.8 sin 314 t volts. Find (a) the RMS voltage, (b) the…
A: It is given that: v=282.8 sin 314 t volts
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A: The solution can be achieved as follows.
Q: For the waveform as shown in the figure 2, If the average voltage is 60.679 volt, Find the value of…
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Q: 5. Determine the rms value for the waveform. i(f) 5 0 1 2 3 4 5 6 7 8 9 10 t
A: RMS value
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A: According to question:
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- ... 0.25 A 120 V 60 Hz RL 1 k2 470 µF When the circuit is working normally, it has an rms secondary voltage of 12.49 volts. Considering the ripple voltage, what is thnimum dc load voltage?If the peak to peak voltage is equal to 20 . How much the RMS value of the voltage!?Computed Rms value (V) 100 E1:A to B E2:A to C 1502 E3:A to D 220. E4:A to F 220 Vac E5:A to G 330 E6:F to G E7:B to C 470 E8:C to D 6802 E9:D to E E10:E to F
- Q13) For the circuit shown in the figure. a) Calculate the ripple factor. b) Sketch and label the output voltage waveform . T1 D1 V1 120Vpk 60HZ 0° 10:1 C1 1G4B42 R1 :100μΕ 1.5kQ 014) Sketch th I the touolA. The value of: A=5 ms C= 15 ms Peak to peak = 10 B D Figure 1 (a) From Figure 1 above, identify the frequency (f), value of time at A, B, C, D, period (T) and the RMS.Get the RMS and average value of the voltage. Frequency is 60 Hz. Please write properly the solution. Make sure to recheck.
- Find the rms of the below voltage waveform A. 0.8165V B 8.165V C 0.9268 D 9.268QUESTION 11 An inductor is connected in parallel with a 6540 resistor and a function generator. The applied voltage is 42V RMS and the total current is 67mA RMS. Find the magnitude of the current through the inductor. Enter your answer in the space provided. Round your answer to one decimal place. Your answer should be in mA but do not enter the unit.iii) A sine waveform with following specifications. RMS voltage 161.4V Time for ten cycles 0.02s Sketch the waveform.
- 2. Determine the rms value for each of the waveforms shown in figure below. (a) e (V) hour 2 2 5 7 10 t (s)Determine the rms voltage across each resistor and the rms current. Make sure to graph the rms voltage and current.8. Liquids with solid impurities a) Have higher dielectric strength b) Of large size have higher dielectric strength c) Have lower dielectric strength as compared to pure liquids d) None of the above 9. Peak to peak ripple is defined as a) the difference between average de voltage and peak value b) the difference between maximum and minimum de voltage c) the difference between maximum ac and average de voltages d) the difference between ac (rms) and average de voltages 10. In a Cockroft-Walton circuit, input voltage 100 kV load current 25 mA, supply frequency 100 Hz, each capacitor 10 nF. The optimum no. of stages for maximum output voltage is a) 1 b) 2 c) 10 d) 35