4-44. The tongs are used to lift the 150-kg crate, whose center of mass is at G. Determine the least coefficient of static friction at the pivot blocks so that the crate can be lifted. 275 mm 500 mm 500 mm 300 mm
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- 4. The mine car and its contents have a total mass of 6000 kg and a centre of gravity at G. If the coefficient of static friction 10 kN between the wheels and the 0.9 m •G tracks is u = 0.4 when the wheels are locked, find the normal force acting on the front wheels at B and the rear 0.15 m 0.6 m - 1.5 m wheels at A when the brakes at both A and B are locked. Does the car move? [Ans. NA = 16.5 kN, Ng =42.3 kN, the car does not move] %3D lypFind the value s so that the worker can climb the ladder without causing it to slip. The weight of the worker is 90-kg and neglect the weight of the ladder. The ladder has a small roller at the top and at the ground the coefficient of static friction is 0.25. The center of mass of the worker is directly above her feet. B 4 m 1.5 mQ1: The tractor has a weight of 4500 lb with center of gravity at G. The driving traction is developed at the rear wheels B, while the front wheels at A are free to roll. If the Q2: The mine car and its contents have a total mass of 9 Mg and a center of gravity at G. If the coefficient of static friction between the wheels and the tracks is u, = 0.4 when the wheels are locked, find the normal force acting on the coefficient of static friction between the wheels at B and the ground is u, = 0.5, determine if it is possible to pull at P = 1350 lb without causing the wheels at B to slip or the front wheels at A to lift off the ground. front wheels at B and the rear wheels at A when the brakes at both A and B are locked. Does the car move? 10 kN 0.9 m G 0.15 m 3.5 ft 1.25 ft 0.6 m- 4 ft -1.5 m- 2.5 ft
- Calculate the magnitude of the force supported by the pin at A under the action of the 1.5-kN load applied to the bracket. Neglect friction in the slot. 180 mm -120 mm-The two 200N blocks are pushed apart by the 15⁰ wedge of negligible weight. The angle of static friction is 12⁰ at all contacts surfaces. Determine the force P required to start the blocks moving.Determine the magnitude of the reaction at the bottom of the ladder. The top of the 15-kg ladder is leaning against a very smooth vertical wall. Assume that the mass center of the painter is directly above his feet and that the coefficient of friction between the horizontal ground and the ladder is 0.25. X entr ara answer: Blank 1 N 15 kg 0.75 m 0.75 m
- The rope running over two fixed cylinders carries the 4-kg mass at one end. Determine the force P that must be applied to the other end to initiate motion. The coefficient of static friction between the rope and the cylinders is 0.15. BISECTION METHODIf the center of gravity of the stacked tables is at G, and the stack weighs 100 lb, determine the smallest force P the boy must push on the stack in order to cause movement. The coefficient of static friction at A and B is s = 0.3. The tables are locked together. Answer: P =300 lb. The coefficients of friction between Aa of P for which the system is in equilibrium. Block 5-14. Both block A and block B of Fig. PS-14 weigh pulley is frictionless. Determine the maximum value B and the floor are 0.4 and 0.6, respectively. The CHAP.S 250 FRICTION and A is homogeneous. 3' P5-14
- Q4: The uniform box shown in next figure, has a mass of 40 Kg. If the two forces T= 60 N and F=30 N are applied on the box, determine if it remains in equilibrium. The coefficient of static friction () = 0.24 T-6ON 40 Kgthe homogeneous cylinder of weight W=100 N rests in a frictionless right angled corner. determine the contact forces NA and NB angle is 30 degreesQ3/. Determine the maximum force P that can be applied without causing movement of the 200 lb crate that has a center of gravity at G. The coefficient of static friction at the floor is u, = 0.4. See figure (3). 1.5 ft 1.5 ft 2.5 ft 4.5 ft 3.5 ft (1) e (2 Fig (3)