Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- A bracket is under a loading condition shown below. It's made from a steel with yield strength (Sy) of 42 ksi and ultimate tensile strength (Sut) of 76 ksi. The diameter is 0.42 in and b = 1.75 in, with the load P fluctuate between 15 lbs (tension) and -5 lbs (compression). Using the modified Goodman or Gerber criterion, determine the fatigue factor of safety based on infinite life. If infinite life is not predicted, estimate the number of cycles to failure. Also check for yielding.arrow_forwardPlease help with all, thank you in advance! Will give thumbs uparrow_forwardQ: Consider an 18-8 Mo stainless steel component (Figure below) that is exposed to an allowable stress level (110 MPa) for a rupture lifetime of 1 year. Write your decision for this metal will be accepted or no at operation temperature of (1000°C). 10 T120 + log t,(*R-h) 25 30 35 40 45 50 100 100 10 10 12 16 20 24 28 10 7120 + log t,XK-h) Sress (MPa)arrow_forward
- Read and Solve carefully please Write clearly and Box the Final answer Express your answer to 3 Significant figures and include appropriate units. QUESTION : Recall that for spings the Zimmerli point on the modified Goodman diagram is located at (Ssm, Ssa) = (55, 35) ksi. Suppose that a particular spring wire has a shear ultimate strength of Ssu = 89 ksi. Determine the shear endurance limit of the spring wire. Give your answer in units of ksi,arrow_forwardRequired information The cold-drawn AISI 1040 steel bar shown in the figure is subjected to an axial load that fluctuates from 8 kN to 30 kN. Use the Modified Goodman criterion and estimate the fatigue factor of safety based on achieving infinite life and the yielding factor of safety. 25 mm 10mm -6-mm D. What is the number of cycles to failure for this part? The number of cycles is 120000arrow_forwardPlease solve all the question handwrittenarrow_forward
- A cylindrical steel bar 8 mm in diameter is loaded 1000 cycles per day with a load of 15560 N. How long until fatigue failure takes place? Note: stress force/area 500 450 400 350 Steel Allby 300 250 200 150 Brass Alloy 100 50 1.00E-07 Cycles to Failure, N 1.00E+04 1.00E+05 1.00E-06 1.00E+08 100E+09 1.00E+10 , The bar should not fatigue. ) The bar will fail in one cycle. ) 100 days ) 1000 days Stress Amplitude, MPaarrow_forwardPart A and B circle final answers The next 2 question relate to the modified Goodman diagram with the following baseline data. A part is made from steel with the following properties: Ultimate tensile strength is 450 MPa Yields stength is 260 MPa Fully-corrected endurance limit is 180 MPa The part is subjected to a time-varying load with σmax = 150 MPa and σmin = 90 MPa . Part A The safety factor with respect to fatigue is?? Part B - the safety factor with respect to yielding is?arrow_forwardCalculate a diameter, d, to ensure that yield does not occur in the 1045 carbon steel (Yield stress = 310 MPa) under 220kN tensile load. Use a factor of safety of 5.arrow_forward
- The fatigue (endurance) limit of a 1045 (plain carbon) stcel is about 300 MN/m² when the mean stress is zero. The tensile strength of this steel is 750 MPa. Using the Goodman equation, estiniate the safe stress amplitude for 1045 steel for the situation of a mean stress of 250 MPa.arrow_forwardParvinbhaiarrow_forwardThe cold-drawn AISI 1040 steel bar shown in the figure is subjected to an axial load fluctuating between 0kN and 28kN. Estimate the fatigue factor of safety based on achieving infinite life using modified Goodman criterion and the yielding factor of safety. If infinite life is not predicted, estimate the number of cycles to failure.arrow_forward
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