Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- for the table below make a graph call it Factors vs Rate of Enzyme Activity rules: data points must be an x or circled dot, must be on grid papaer and half the page minimum size, the independant variable on the x axis and dependant variable on the y axis, must include titlesarrow_forward2. The enzymatic reaction rate r is given by equation 2 below as a function of substrate concentration Cs and kinetics parameters KM and rmax. Using linear and nonlinear regression in excel, evaluate the kinetic parameter constants of a biosystem given the gathered data from a series of batch runsarrow_forwardSUBSTRATE CONCENTRATION [S] µM INITIAL VELOCITY V0 s-1 10 0.13 25 0.27 50 0.45 100 0.65 150 0.77 200 0.85 300 0.94 500 1.03 (i) a) Construct an empty table with the following column headings: Substrate concentration [S] and initial velocity (Vi) where [S] has the unit µM, and Vi has the unit mM/s. (ii) The table provided is the enzyme kinetic data for your mutated enzyme, whereby Vi was expressed using the unit ∆A(405 nm)/s. Using the standard curve, express Vi with the unit mM/s rather than ∆A(405 nm)/s. Place your answer in the table above alongside the appropriate [S]. Hint: To answer this question you need to use this standard curve equation=0.0419x (The slope of the line is= 0.0419) (iii) The unmutated form of your protein has a Km of 25 µM and a Vmax of 43 mM/s. The enzyme kinetic data for your enzyme with the amino acid substitution should now be displayed in the table above. Based on these data, what is Vmax? Km? and…arrow_forward
- Batch culture time prediction: A strain of Escherichia coli has been genetically modified to produce human protein. A batch culture is started by inoculating 12 g of cells into a 100 liters bubble column fermenter containing 10 g/l glucose. The culture does not exhibit a phase lag. The maximum specific growth rate of the cells is 0.9 h^-1, the glucose biomass yield is 0.575 g/g. Estimate the time required to reach the stationary phase.arrow_forwardThe hydrolysis of a substrate, S, by an enzyme has been studied in the lab. The following initial rates, vo, were recorded at different concentrations. [S] (M) Vo (M/min) 2.10-10-4 1.20.10-6 4.20-10-4 3.10.10-6 9.30-10-4 6.30-10-6 1.42-10-3 9.10-10-6 A. Determine the rate constants for degradation of the substrate B. What is the rate of reaction at [S] = 1.1.104 M? C. Explain, why enzymes can make reactions go faster? Does enzymes also catalyse the reverse reaction from product to substrate?arrow_forwardIf we examine all of the enzymes involved in the CAC as it's own isolated pathway. What would be the sum of the Flux Control Coefficients (C) of all the enzymes involved in this pathway? O 2.3 O 0.4 O 1.5 1.0 O 0.0arrow_forward
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