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3. For the reaction we studied: 21- + S₂08²- - I2 + 2 SO4²- A. Use this value and your experimental activation energy value to draw an energy profile for the reaction with the energies appropriately scaled on the vertical axis. Ea=-58.86 15/mol B. Label AHrxn and Ea on the graph. Energy Reaction Progress → AHrxn = -322 kJ/mol rxn →-322,000 C. Calculate the Ea for the reverse reaction mol

3. For the reaction we studied: 21- + S₂08²- - I2 + 2 SO4²- A. Use this value and your experimental activation energy value to draw an energy profile for the reaction with the energies appropriately scaled on the vertical axis. Ea=-58.86 15/mol B. Label AHrxn and Ea on the graph. Energy Reaction Progress → AHrxn = -322 kJ/mol rxn →-322,000 C. Calculate the Ea for the reverse reaction mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3. For the reaction we studied: 21 S₂O8²-> I2 + 2 SO4²- A. Use this value and your experimental activation energy value to draw an energy profile for the reaction with the energies appropriately scaled on the vertical axis. Ea = -58.86 15/mol B. Label AHrxn and Ea on the graph. Energy Reaction Progress → AHrxn= -322 kJ/mol rxn-322,000T C. Calculate the Ea for the reverse reaction mol
Transcribed Image Text:3. For the reaction we studied: 21 S₂O8²-> I2 + 2 SO4²- A. Use this value and your experimental activation energy value to draw an energy profile for the reaction with the energies appropriately scaled on the vertical axis. Ea = -58.86 15/mol B. Label AHrxn and Ea on the graph. Energy Reaction Progress → AHrxn= -322 kJ/mol rxn-322,000T C. Calculate the Ea for the reverse reaction mol
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