3. (a) How much heat must be absorbed by ice of mass m=800 g at –20°C to take it to the steam at 120°C ? Given the specific heat of ice is 2220 J/kg.K, specific heat of water is 4186 J/kg.K, specific heat of steam is 1996 J/kg.K, the latent heat of fusion is 333 KJ/kg and latent heat of vaporization is 226 KJ/kg. (b) If we supply the ice a total energy of only 310 KJ, what are the final state and temperature of the water?

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
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3. (a) How much heat must be absorbed by ice of mass m=800 g at -20°C to take it to the steam at 120°C
? Given the specific heat of ice is 2220 J/kg.K, specific heat of water is 4186 J/kg.K, specific heat of steam
is 1996 J/kg.K, the latent heat of fusion is 333 KJ/kg and latent heat of vaporization is 226 KJ/kg. (b) If we
supply the ice a total energy of only 310 KJ, what are the final state and temperature of the water?
Transcribed Image Text:3. (a) How much heat must be absorbed by ice of mass m=800 g at -20°C to take it to the steam at 120°C ? Given the specific heat of ice is 2220 J/kg.K, specific heat of water is 4186 J/kg.K, specific heat of steam is 1996 J/kg.K, the latent heat of fusion is 333 KJ/kg and latent heat of vaporization is 226 KJ/kg. (b) If we supply the ice a total energy of only 310 KJ, what are the final state and temperature of the water?
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