3. a) Define electric displacement vector D and deduce Gauss's law for dielectrics.b) A dielectric of dielectric constant 5.0 is filled in the gap between the plates of acapacitor. Calculate the factor by which the capacitance is increased, if thedielectric is only sufficient to fill up 1/5 of the gap.c) A 1.0 m length of current-carrying wire kept perpendicular to a magnetic field ofmagnitude 400 mT experiences a force of 3.0 mN. Determine the current flowing ithe wire.

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Answered: 3. a) Define electric displacement…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Please see attached question.
Q3 Part b please
4. Suppose that the clectric ficld can be obtained from a voltage, such that E = -VV. What is V x E, in that casc? Note: every electric ficld that we have encountered, so far, has bcen derivable from a potential. However, we will soon encounter induced clectric ficlds that are not. In that case, the curl of the clectric ficld will not be the answer you found for this problem.
Q.4 (a) Draw and label a gold leaf electroscope. Explain how such an instrument can be used to distinguish between an insulator, a poor conductor and a good conductor (b) Describe and explain what happens when the terminals of a charged capacitor are connected by a piece of copper wire (c) Plates were fixed on the top and bottom of a cubical box with each side equal to 2 cm. A capacitor was constructed out of this box by filling it with a suitable dielectric material. In an experiment with this capacitor, the charge stored was measured and the electric field between the plates was determined as the charging potential difference was varied. The results are tabulated below. Charge stored/uC 7.5 30 60 75 90 Electric 0.5 2.0 4.0 5.0 6.0 field/Vcm-1 Plot a suitable graph which can be used to determine the dielectric strength, and hence the capacitance of the capacitor used in this experiment. Calculate the total energy stored by the capacitor when the electric field is 400 V/m.
Consider what happens when a person moves around in dry conditions. The rubbing of motion leads to static electric charge building up on the body. Assume the capacitance of the human body to be about 155 pF. a) How much charge would have to build up on a body to generate a potential difference of 10 kV? b) A particular cell phone can have its circuits destroyed if exposed to an electric shock containing 300 u.J of energy. What voltage does that correspond to if the shock is coming from a human body?
944 An infinitely long coaxial cylinder (radius of the inner conductor = a & radius of the outer conductor = b, where b/a = e & dielectric constant = E) is connected to a DC voltage source of emf (a) EDP&V in the dielectric region between the two conductors. b The surface charge densities on the two conductor surfaces. The capacitance per unit meter of this coaxial structure. (d Use the virtual displacement method to find the force on the inner conductor. %3D = V, as shown in figure. Use Poisson's equation to find:
B) Two voltage vectors Va and Vb combine to form a resultant vector Vr. Va = 110V Vb = 230 V Vb is at an angle of 45 degrees from the horizontal. Apply the cosine rule to determine the length of Vr and the angle between Va and Vr. Your Answer: Vr Va Vb
is linearly proportional to A capacitor with plates separated by distance d is charged to a potential difference AVc. All wires and batteries are disconnected, then the two plates are pulled apart (with insulated handles) to a new separation of distance 2d. is inversely proportional to does not depend on increases by a factor of 2. decreases by a factor of 2. does not change. The electric field strength E of a parallel plate capacitor the separation of its plates. That is, E
ELECTRICITY AND MAGNETISM. QUESTION. Two capacitors, one charged and the other u charged are connected in parallel. Prove that when equilibrium is reached, each capacitor carries a fraction of the initial charge equal to the ratio of its capacitance to the sum of the two capacitances. Show that the final energy is less than the initial energy, and derive a formula for the difference in terms of the initial charge and the capacitances of the capacitors.
University of physics question 24.11 To start.. I AM BLIND AND CAN'T SEE IMAGES/GRAPHICS ON HERE. Could you explain this to me with html text? Would really help me and others out. So the question goes: A cylindrical capacitor has an inner conductor of radius 2.6 mmmm and an outer conductor of radius 4.0 mmmm. The two conductors are separated by vacuum, and the entire capacitor is 3.0 mm long. Part A Part complete What is the capacitance per unit length? I got 130 pf/m for that but am confused for part b: Part B The potential of the inner conductor relative to that of the outer conductor is 350 mVmV. Find the charge (magnitude and sign) on the inner conductor. Express your answer with the appropriate units. What needs to be done for that part? I can't seem to figure out what i need to use for that portion. Also.. NO PICTURES WERE GIVEN EITHER.

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