A parallel-plate air capacitor is made from two plates 0.250 mmsquare, spaced 0.900 cm apart. It is connected to a 140 VVbattery. If the battery is disconnected and then the plates are pulled apart to a separation of 1.50 cm, what is the capacitance, what is the charge on each plate, what is the electric field between the plates, and what is the energy stored in the capacitor?

(a )A researcher connects a 3.00 V battery to the plates of a capacitor. After waiting a while, the capacitor reaches a maximum amount of 16.0 µC of stored charge. What is the value of the capacitance (in µF)? µF (b) The capacitor is disconnected from the battery, discharged, and then connected to a 10.0 V battery. Again, a long enough time is waited for the capacitor to fully charge. How much charge (in µC) is stored now? (Assume the capacitor can handle this new voltage without failing.) µC

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A 10 V battery is connected to a series of n capacitors, each of capacitance 2.0 mF. If the total stored energy is 25 mJ, what is n?

A 0.8 µF capacitor is charged to 15 V. After charging, the capacitor is disconnected from the voltage source and is connected to another uncharged capacitor. The final voltage is 5 V. (a) What is the capacitance of the other capacitor? µF (b) How much energy was lost when the connection was made? µJ еВook

A 2.0- cm- diameter parallel-plate capacitor with a spacing of 0.50mm is changed the 200 V What is the total energy stored in the electric field? What is the energy density?

A parallel plate capacitor has a charge Q, and a voltage difference AV. The gap is air-filled with an electric field E. 1. The capacitor is then disconnected from the circuit so that there is no path for the electrons to move from one plate to another. An insulator of dielectric constant *> 1 is then inserted to fill the entire gap. The electric field in the gap will cause the charges in the dielectric to separate slightly. This leaves an excess layer of negative charges on the top of the insulator and an excess layer of positive charges at the bottom surface of the insulator. This induced surface charge creates an induced electric field opposite the direction of the original electric field. a. The new net electric field is Ē' = Z₂ + Ēinduced. Which is true of E', the magnitude of the new net field? Choose one. E' = E, (the net electric field is the same as the original electric field) E' = E₁/x (the net electric field is smaller than the original field.) b. Which is true of the new…

Four identical 2.5-mF capacitors are connected together electrically. What is the greatest possible capacitance of the combination?

A parallel-plate capacitor is made of two square plates25 cm on a side and 1.0 mm apart. The capacitor is connected to a 50.0-V battery. With the battery still connected, the plates are pulled apart to a separation of 2.00mm. What are the energies stored in the capacitor beforeand after the plates are pulled farther apart?

You have two parallel plate capacitors, C 1a = 10 nF and C 2a = 20 nF, each with the same area of 2 m^2 that is filled with a dielectric material that is 1 mm thick.   a) If the capacitors are connected in series vs parallel, which provides more total capacitance?   b) What is the difference in total energy if the capacitors are connected in series vs. parallel?   c) What dielectric material would you use in order to make the total capacitance of the capacitors connected in series equal to if they were connected in parallel?  Help...