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T
CW
T
3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite
ends as shown below. How far from the seesaw's center of mass must the fulcrum be
placed?
CCW
0
A
60lb
T = 60* (x + 6) +20 * x = 80x + 360
CCW
201b
X
= 180 (6-x) = 1080 - 180x
= Tw
12ft
180lb
80x + 360 = 1080 - 180xx=2.77 ft.
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Transcribed Image Text:T CW T 3. A 12 ft, 20 lb seesaw is balanced by a little girl (60 lb) and her father (180 lb) at opposite ends as shown below. How far from the seesaw's center of mass must the fulcrum be placed? CCW 0 A 60lb T = 60* (x + 6) +20 * x = 80x + 360 CCW 201b X = 180 (6-x) = 1080 - 180x = Tw 12ft 180lb 80x + 360 = 1080 - 180xx=2.77 ft.
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