22. If 75 mls of 0.02 M HCI is added to 425 mls of 0.5 M glycine buffer at pH 10.4, what is the resultant pH? (pK1 for Gly= 2.2, PK2=9.4)

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter17: Introduction To Iv Therapy
Section: Chapter Questions
Problem 3.6P
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22. If 75 mls of 0.02 M HCI is added to 425 mls of 0.5 M glycine buffer at pH 10.4, what is
the resultant pH? (pK1 for Gly= 2.2, Pk2=9.4)
Gly 425LX.5mol/l = .2125 mol
HCI .075LX.02 mol/L = .0015mol
start
end
Glyº
.02125mol
+.0015mol
.02275mol
Gly-
.19125mol
-.0015mol
pH = pka + log[A-]/[HA] = 9.4 + log .18975/.02275
pH = 10.31
.18975mol
Transcribed Image Text:22. If 75 mls of 0.02 M HCI is added to 425 mls of 0.5 M glycine buffer at pH 10.4, what is the resultant pH? (pK1 for Gly= 2.2, Pk2=9.4) Gly 425LX.5mol/l = .2125 mol HCI .075LX.02 mol/L = .0015mol start end Glyº .02125mol +.0015mol .02275mol Gly- .19125mol -.0015mol pH = pka + log[A-]/[HA] = 9.4 + log .18975/.02275 pH = 10.31 .18975mol
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