2.4 How many moles of gas would be produced if this amount of sodium bicarbonate reacted completely with acetic acid, which you added as vinegar? Jdeal Gas law Re 0.0821Lat m mol.k. PV- nRT P= 1.013x 105 Molar mass of MaHCOB Na HCO8 OBRD 84.00 glmol %3D 2.5 What volume would this amount of gas occupy at room temperature (25.0 °C)? At refrigerator temperatures (4.0 °C)? Or at freezer temperature (-20.0 °C)? 2 1.013x 105 ppessre

Q: (4.80 x 10^{-107}) X (5.00 x 10^{-11})= a 2.40 x 10^{-96} b 24.0 x 10^{-96} c 2.40 x 10^{-118} d 2.40 x 10^{-117}

zinc sulfate + iron bromide precipate

t-BUOK CI t-BUOH

1 please assist with number one in the picture.  I want to be we are correct. This is not a graded question as it is a practice question . I am 60 years old and helping my son prepare for the AP exam in a few months. We do questions at the back of the textbook by Zumdahl and Zumdahl

Volume of Water(mL)=100mL Initial temp of water (C)= 21 C degrees Mass of metal(g)=2.9grams Final temp of water and metal(C)=38 C degrees The water absorbed/released (circle one)_____________J of energy. That was absorbed/released (circle one) by the metal. Therefore, (q)metal=________J. We have to assume the temperature of the metal initially is the same temp. of boiling water, 100.0 C degrees, calculate the change in temp. of the metal.

( 5.31 × 10 8 ) + ( 6.53 × 10 7 )

2-

Thank you I got the correct answer however I am unable to get the same answer on my calculator. I keep getting 3.1645425X10^-54. I don't know what I am plugging in incorrectly.  This is what I plug in (6.626X10^-34)/(1.67X10^-27)(9.11X10^6)