Volume of Water(mL)=100mL Initial temp of water (C)= 21 C degrees Mass of metal(g)=2.9grams Final temp of water and metal(C)=38 C degrees The water absorbed/released (circle one)_____________J of energy. That was absorbed/released (circle one) by the metal. Therefore, (q)metal=________J. We have to assume the temperature of the metal initially is the same temp. of boiling water, 100.0 C degrees, calculate the change in temp. of the metal.
Volume of Water(mL)=100mL Initial temp of water (C)= 21 C degrees Mass of metal(g)=2.9grams Final temp of water and metal(C)=38 C degrees The water absorbed/released (circle one)_____________J of energy. That was absorbed/released (circle one) by the metal. Therefore, (q)metal=________J. We have to assume the temperature of the metal initially is the same temp. of boiling water, 100.0 C degrees, calculate the change in temp. of the metal.
ChapterU5: Fire: Energy , Thermodynamics, And Oxidation-reduction
Section: Chapter Questions
Problem 4STP
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Volume of Water(mL)=100mL
Initial temp of water (C)= 21 C degrees
Mass of metal(g)=2.9grams
Final temp of water and metal(C)=38 C degrees
The water absorbed/released (circle one)_____________J of energy. That was absorbed/released (circle one) by the metal. Therefore, (q)metal=________J. We have to assume the temperature of the metal initially is the same temp. of boiling water, 100.0 C degrees, calculate the change in temp. of the metal.
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