2. In the Dehydrohalogenation of 2-Bromobutane, the same three products are obtained. Write a reasonable mechanism for the formation of these products. Make sure you show all intermediates, formal charges, and use curved arrows to track the flow of electrons. Base Br

How do you do the Mechanism? Please do the Full Reaction so I can see whats going on also, dont forget the arrows and the intermediates and formal charges, because honestly I'm fully lost with this....

In parts 1 and 2 draw the two organic products of this reaction, showing any nonzero formal charges. Then, in part 3 answer the question regarding purification of the reaction mixture. 1. Draw the product with the higher molecular weight here 2. Draw the product with the lower molecular weight here 3. Which method would be the simplest and most effective means to best separate the two products? (extraction, recrystallization, chromatography, distillation)

Propose a structure for an aromatic hydrocarbon, C3H10, that can form three C3H,Br products on substitution of a hydrogen on the aromatic ring with bromine. • You do not have to consider stereochemistry. In cases where there is more than one answer, just give one. • Ignore the ortho, para-directing effects of the alkyl groups in answering this question. Consider only the number of nonequivalent hydrogens on the aromatic ring. .... ChemDoodle

Change the structure below to show the most stable form of this carbocation intermediate.

For #9. use ONLY reactions we have studied this semester. 9. a) Write out seven separate reactions of 1-pentene, including reagent(s) and products(s). Include stereochemistry where relevant. b) Write out five separate reactions of 1-pentyne, including reagent(s) and product(s). Include stereochemistry if relevant.

Draw a structural formula for the major product of the acid-base reaction shown. NH2 NH2 ( 1 mole) CH3 ( 1 mole) + HCI (1 mole) You do not have to consider stereochemistry. • Do not include counter-ions, e.g., Na', I, in your answer. • In those cases in which there are two reactants, draw only the product from the compound that reacts. + ▾ % [ ]*

Dehydration of alcohols is the reverse reaction of the hydration of an alkene. Typical reaction conditions include heating the alcohol in the presence of a strong acid, which will produce an alkene product. In this tutorial we will explore 1. the dehydration of secondary and tertiary alcohols 2. when mixture of products are expected and how to determine the major product 3. when rearrangements are expected and how to determine the major product 4. the dehydration of primary alcohols Put it all together. The alcohol shown can form several dehydration products. Draw the major dehydration product. If cis or trans alkene isomers are formed, clearly draw the major isomer. OH H₂SO4

Draw the structure of the intermediate that forms in the first step of the reaction mechanism and the product.  The electrophilic addition reaction in question 3, proceeds through two intermediates and three discrete mechanism steps. Using curved arrow formalism, draw the reaction mechanism for the transformation in question 3 with Br2 and H2O.

Please don't provide handwriting solution